This is a simple proportion problem. On the left side of the colon : there's a 1 and xy. On the right it's yz and a 2. This means for every one xy there will be two yz. So, if there are 2 xy there are 4 yz
<h3>Given</h3>
<h3>Find</h3>
<h3>Solution</h3>
It can be convenient to rewrite f(x) as a square, then do the substitution. That way, the algebra is simplified a little bit.
... f(x) = (x +1)²
... f((2a-3)/5) = ((2a-3)/5 +1)² = ((2a -3 +5)/5)²
... = (2/5(a+1))²
... f((2a-3)/5) = (4/25)(a² +2a +1)
Answer:
f(5) = 20
f(-4) = 2
Step-by-step explanation:
I assume the equation is f(x) = 2x + 10 (Not sure why the "{" is there.)
f(5) = 2*5+10
f(5) = 20
f(-4) = 2*(-4) + 10
f(-4) = 2
