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liberstina [14]
4 years ago
6

Solve for x. −34(x+2)=6 will give brainliest

Mathematics
2 answers:
ANTONII [103]4 years ago
4 0
The answer is bold 
-34(x+2)=6
x= -37/17

Steps
-34(x+2)=6
-34x-68=6
-34x=6+68
-34=74
<span>x=-37/17</span>

Alternative form is
x=-2 3/17 x = 2.17647 
stealth61 [152]4 years ago
3 0
Let's solve your equation step-by-step.<span><span>−<span>34<span>(<span>x+2</span>)</span></span></span>=6</span>Step 1: Simplify both sides of the equation.<span><span>−<span>34<span>(<span>x+2</span>)</span></span></span>=6</span><span>Simplify: (Show steps)</span><span><span><span>−<span>34x</span></span>−68</span>=6</span>Step 2: Add 68 to both sides.<span><span><span><span>−<span>34x</span></span>−68</span>+68</span>=<span>6+68</span></span><span><span>−<span>34x</span></span>=74</span>Step 3: Divide both sides by -34.<span><span><span>−<span>34x</span></span><span>−34</span></span>=<span>74<span>−34</span></span></span><span>x=<span><span>−37</span>17</span></span>Answer:<span>x=<span><span>−37/</span><span>17


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Answer:

15a+12ac+6ab

Step-by-step explanation:

3a(5 + 4c + 2b)

5*3a = 15a

4c*3a = 12ac

2b*3a = 6ab

6 0
3 years ago
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Pleaseeee helpppp !!!!!!!! Will mark Brianliest !!!!!!!!!!!!!
Goryan [66]

Answer:

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Step-by-step explanation:

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Graph the inequality y &gt; |x + 1| – 1. Which point is NOT part of the solution? (–1, 2) (1, −1) (–1, 0) (1, 3)
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4 years ago
<img src="https://tex.z-dn.net/?f=0.6%20%5Csqrt%7B33.54%7D%20" id="TexFormula1" title="0.6 \sqrt{33.54} " alt="0.6 \sqrt{33.54}
ki77a [65]

0.6\sqrt{33.54}

=5.79137

0.6*5.79137

=3.4

Hope this helps!

Thanks!

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3 years ago
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Makovka662 [10]

Answer:

R=\frac{QJ}{I^2t}

Step-by-step explanation:

So we have the equation:

Q=\frac{I^2Rt}{J}

And we want to solve for R.

First, let's multiply both sides by J to remove the fraction on the right. So:

(J)Q=(J)\frac{I^2Rt}{J}

Simplify the right:

JQ=I^2Rt

We can rewrite our equation as:

JQ=R(I^2t)

So, to isolate the R variable, divide both sides by I²t:

\frac{JQ}{I^2t}=\frac{R(I^2t)}{I^2t}

The right side cancels, so:

R=\frac{QJ}{I^2t}

And we are done!

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3 years ago
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