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1 year ago

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Find the 14th term of the geometric sequence 5, -10, 20 (Please helpp)

1 answer:

Kisachek [45]1 year ago

5 0

Answer: The general formula for exponential sequence or GP is

GP = arn-1 , ie ar raised to the power of n-1 where a is the first term , r is the common ratio and n is the number of terms. Now to find the 14th term we first find the common ratio (r) by dividing the second term by the first term of third by second term.

r = -10/5

=. -2.

Since n is 14-1 = 13. and a is 5
we now put those values in the formula to find the 14th term

T14 = ar^n-1

= 5 x (-2)^13

= 5 x -8192

=. -40,960

There the 14th term of the GP sequence

= -40,960

Step-by-step explanation:

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2 years ago

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2 years ago

Nutka1998 [239]

Answer:

$m\angle MEJ=25^{\circ}.$

Step-by-step explanation:

The arcs LY, KM, KL and MJ together form the full revolution angle, thus

$4x+50^{\circ}+6x+x+10^{\circ}+4x=360^{\circ},\\ \\15x=300^{\circ},\\ \\x=20^{\circ}.$

Note that

$m\angle MOJ=4x=80^{\circ},$

then

$m\angle MLJ=\dfrac{1}{2}\cdot 80^{\circ}=40^{\circ}.$

So,

$m\angle ELM=180^{\circ}-40^{\circ}=140^{\circ}.$

Also

$m\angle LOK=30^{\circ},$

so

$m\angle KML=\dfrac{1}{2}\cdot 30^{\circ}=15^{\circ}.$

In triangle EML,

$m\angle MEL+m\angle EML+m\angle ELM=180^{\circ},\\ \\m\angle MEL=180^{\circ}-15^{\circ}-140^{\circ}=25^{\circ}.$

Thus, $m\angle MEJ=25^{\circ}.$

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3 years ago