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Kryger [21]
3 years ago
7

What is the value of X?

Mathematics
1 answer:
Feliz [49]3 years ago
3 0

Answer:

-2

Step-by-step explanation:

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10) Find the distance between (2, 3) and (-3, -2) A) 2 B) 5 C) 50 = 5 2 D) 25
PSYCHO15rus [73]

Answer:

The answer is

<h2>5 \sqrt{2}  \:  \:  \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(2, 3) and (-3, -2)

The distance between them is

d =  \sqrt{( {2 + 3})^{2} +  ({3 + 2})^{2}  }  \\  =  \sqrt{ {5}^{2}  +  {5}^{2} }  \\  =  \sqrt{25 + 25}  \\  =  \sqrt{50}  \\  = 5 \sqrt{2}

We have the final answer as

5 \sqrt{2}  \:  \:  \:  \: units

Hope this helps you

6 0
4 years ago
Please help me with alg 2 question!
AlladinOne [14]

Answer:

J

Step-by-step explanation:

3 0
2 years ago
What is the slope of the line through ( -2.1) and (2, -5)
nordsb [41]

Answer:

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6 0
3 years ago
The cost function for a certain company is C = 20x + 700 and the revenue is given by R = 100x − 0.5x2. Recall that profit is rev
Sladkaya [172]

Answer:

The two values of production level are:

x = 20

or

x = 140

Step-by-step explanation:

Let's write the Profit equation by subtracting the cost function from the revenue one:

Profit(x)=100\,x-0.5\,x^2-(20\,x+700)\\Profit(x)=-0.5\,x^2+80\,x-700

Now, we set to find the production level "x" to give us a profit of $ 700:

Profit(x)=-0.5\,x^2+80\,x-700\\700=-0.5\,x^2+80x-700\\0.5\,x^2-80\,x+1400=0

So we solve this quadratic equation using the quadratic formula:

x=\frac{80+/-\sqrt{80^2-4(0.5)(7700)}}{2\,*\,0.5} \\x=80+/-\sqrt{3600} \\x=80\,+/-\,60

which gives two posible solutions: x = 20, or x = 140

6 0
4 years ago
Need help asappppppp ​
Marat540 [252]

Answer:

what do you need help with

Step-by-step explanation:

in order for me to answer you need to pit the problem

6 0
3 years ago
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