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➷ First identify and assign the variables:
q = number of quarters
d = number of dimes
This is what we know:
q + d = 22
A quarter is 25 cents and a dime is 10 cents
You can write this as:
0.25q + 0.1d = 3.40
Rearrange the first equation for d
d = 22 - q
Substitute this value into the other equation:
0.25q + 0.1(22 - q) = 3.40
Simplify:
0.25q + 2.2 - 0.1q = 3.40
0.15q + 2.2 = 3.4
Subtract 2.2 from both sides:
0.15q = 1.2
Divide both sides by 0.15:
q = 8
Substitute into the first equation:
8 + d = 22
d = 14
Therefore, there are 8 quarters and 14 dimes.
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2.) A. 32 cm
3.) D. 6.4
4.) B.) 7
5.) 22.75
6.) 3
I’ll show u a picture of how I solved everything. Ask any questions if needed.
Answer:
I think they both have the same amount walked, therefore they are both considered as they have walked the same distance
Step-by-step explanation:
Answer:
Cost of 1 rose bush = x = $5
Cost of 1 geraniums = y = $2
Step-by-step explanation:
DeShawn and Mike each improved their yards by planting rose bushes and geraniums. They bought their supplies from the same store.
Let us represent:
Cost of 1 rose bush = x
Cost of 1 geraniums = y
DeShawn spent $13 on 1 rose bush and 4 geraniums.
x + 4y = 13..... Equation 1
x = 13 - 4y
Mike spent $56 on 10 rose bushes and 3 geraniums.
10x + 3y = 56....... Equation 2
We substitute 13 - 4y for x in Equation 2
10(13 - 4y) + 3y = 56
130 - 40y + 3y = 56
Collect like terms
- 40y + 3y = 56 - 130
-37y = -74
y = -74/37
y = $2
Solving for x
x = 13 - 4y
x = _13 - 4 × $2
x = $13 - $8
x = $5
Therefore,
Cost of 1 rose bush = x = $5
Cost of 1 geraniums = y = $2
Answer:
There is no sufficient evidence to support the claim.
Step-by-step explanation:
Given the data:
7.91, 7.85, 6.82, 8.01, 7.46, 6.95, 7.05, 7.35, 7.25, 7.42
Sample size, n = 10
The sample mean, xbar = ΣX/ n = 74.07 / 10 = 7.407
The sample standard deviation, s = 0.41158 ( from calculator)
The hypothesis :
H0 : μ = 7
H0 : μ ≠ 7
The test statistic :
(xbar - μ) ÷ (s/√(n))
(7.047 - 7) ÷ (0.41158/√(10))
0.047 / 0.1301530
Test statistic = 0.361
Testing the hypothesis at α = 0.05
The Pvalue ;
df = n - 1 ; 10 - 1 = 9
Two tailed test
Pvalue(0.361, 9) = 0.7263
Since the Pvalue > α ; we fail to reject the Null and conclude that there isn't sufficient evidence to support the claim.
