Ask question

Ask question

All categories

1 year ago

13

The graph shows the distribution of the number of text messages young adults send per day. The distribution is approximately Nor

mal, with a mean of 128 messages and a standard deviation of 30 messages.
A graph titled daily text messaging has number of text on the x-axis, going from 8 to 248 in increments of 30. Data is distributed normally. The highest point of the curve is at 128.

What percentage of young adults send between 128 and 158 text messages per day?
34%
50%
66%
68%

1 answer:

erik [133]1 year ago

4 0

The percentage of young adults send between 128 and 158 text messages per day is; 34%

<h3>How to find the percentage from z-score?</h3>

The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.

We are given;

Sample mean; x' = 158

Population mean; μ = 128

standard deviation; σ = 30

We want to find the area under the curve from x = 248 to x = 158.

where x is the number of text messages sent per day.

To find P(158 < x < 248), we will convert the score x = 158 to its corresponding z score as;

z = (x - μ)/σ

z = (158 - 128)/30

z = 30/30

z = 1

This tells us that the score x = 158 is exactly one standard deviation above the mean μ = 128.

From online p-value from z-score calculator, we have;

P-value = 0.34134 = 34%

Approximately 34% of the the population sends between 128 and 158 text messages per day.

Read more about p-value from z-score at; brainly.com/question/25638875

#SPJ1

You might be interested in

The LMC of 9 and 7

rodikova [14]

Answer:

63

Step-by-step explanation:

7 0

3 years ago

You roll two fair dice, one green and one red. (a) Are the outcomes on the dice independent? Yes No (b) Find P(1 on green die an

ASHA 777 [7]

Answer:

a

Yes

b

$P(1 \& 5) = \frac{1}{36}$

c

$P(5 \& 1) = \frac{1}{36}$

d

$P(5 \& 1 | 1\& 5 ) = \frac{1}{18}$

Step-by-step explanation:

From the question we are told that

Two fair dice, one green and one red were rolled

Generally the outcomes on the dice independent because the outcome on the first dice is not affected by the second die

Generally the probability of getting a 1 on a dice rolled is $P(1) = \frac{1}{6}$

the probability of getting a 5 on a dice rolled is $P(5) = \frac{1}{6}$

Generally the probability of P(1 on green die and 5 on red die) is mathematically represented as

$P(1 \& 5) = \frac{1}{6} *\frac{1}{6}$

$P(1 \& 5) = \frac{1}{36}$

Generally the probability of P(5 on green die and 1 on red die) is mathematically represented as

$P(5 \& 1) = \frac{1}{6} *\frac{1}{6}$

$P(5 \& 1) = \frac{1}{36}$

Generally the probability of P((1 on green die and 5 on red die) or (5 on green die and 1 on red die)) is mathematically represented as

$P(5 \& 1 | 1\& 5 ) = \frac{1}{36} + \frac{1}{36}$

$P(5 \& 1 | 1\& 5 ) = \frac{1}{18}$

8 0

3 years ago

There is 5/6 of an apple pie left from dinner. Tomorrow, Victor plans to eat 1/6 of the pie that was left. How much of the whole

Lady_Fox [76]

5/6 = 83%
1/6= 16%

83% of the apple pie was left from dinner.
Victor is gonna eat 16% of the pie tomorrow
You have to subtract 16% from 83%
In other words 5/6-1/6

The denominators are same so you don't have to do anything to them
5/6 - 1/6

5-1=4

4/6 of the pie would be left
In simplest form it would be

4/6 <span> ÷2</span>
=2/3

2/3 is in simplest form

5 0

3 years ago

Read 2 more answers

A line with a slope of -1 passes through the point (2,-1). If (-4, p) is another point on the line,

Thepotemich [5.8K]

$(\stackrel{x_1}{2}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{p}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{p}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{-4}-\underset{x_1}{2}}}~~= ~~\stackrel{\stackrel{m}{\downarrow }}{-1}\implies \cfrac{p+1}{-6}=-1\implies p+1=6\implies p=5$

7 0

2 years ago

Karen purchased a used vehicle that depreciates under a straight line method the initial value if the car is 4400 and the salvag

emmasim [6.3K]

It is expected to depreciate from 4400 to 800 in 6 years. The depreciation per year is the ratio
depreciation per year = (total depreciation) / (number of years)

The total depreciation is the change in value, so the depreciation per year is
(4400 - 800)/6 = 600

Karen expects the vehicle to depreciate by 600 each year.

4 0

3 years ago

Read 2 more answers