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elixir [45]
3 years ago
14

Jerry walked 1.5 mailed directly west. Than he walked 1.5 miles east. At this point how many miles did Jerry walk

Mathematics
1 answer:
choli [55]3 years ago
8 0

Answer: 3

Step-by-step explanation:

1.5+1.5=3

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Someone help me fast please
lions [1.4K]

Answer:

86

Step-by-step explanation:

<u>Perimeter of WXY = WSY+WRX+XY</u>

<em>--> WSY = SY x 2</em>

--> WSY = 16 x 2 = 32

<em>Since it is an isosceles triangle, WRX = WSY</em>

--> WRX = 32

<em>--> Draw a straight line from W to XY to divide it into two halves assuming it to be point A. This would form a right angle triangle of WAX.</em>

<em>--> Solve it using the cos theta rule</em>

--> Angle = Angle X = 70°

    Hypotenuse = WRX = 32

    Adjacent = WA = ?

<em>--> Cos (Angle) = Adjacent/Hypotenuse</em>

    Cos (70) = WA/32

    WA = 10.9 rounded off to 11

--> WA=AY= 11

--> XY = WA + AY = 11+11 = 22

<em>--> Perimeter = WSY+WRX+XY</em>

    Perimeter = 32+32+22

    Perimeter = 86

Therefore, the perimeter of WXY is 86.

4 0
3 years ago
Apply the distributive property to factor out the greatest common factor<br><br> 9-12x+6y
Amiraneli [1.4K]
If you decompose 9 you will get 3*3 so 9=3*3
If you decompose 12 you will get 2*6,then you can decompose 6 which 2*3 so 12=2*2*3
If you decompose 6 you will get 2*3 so 6=2*3
What do all of these numbers have in common?The 3.
So 3 is the greatest common factor.Now you just put the 3 in front and then open the bracket and divide each of the number by 3.
9/3=3
-12x/3=4x
6y/3=2y
So,this will be your answer 3(3-4x+2y)
8 0
3 years ago
If m ∠ 8 = 65 degrees, what is m ∠ 5 ? (Image in details)
Nitella [24]
65°

It's opposite on a 180° line. 
7 0
3 years ago
An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec
SVETLANKA909090 [29]

Answer:

The probability mass function is given by

P(X = 0) = 0.003, P(X = 1) = 0.164, P(X = 2) = 0.833

Step-by-step explanation:

Given to us are two mechanical components.

The probability of the first component meeting the given specifications are 0.98.

The probability that the second component meets the given specifications  = 0.85.

In the information given the components are said to be independent.

The probability mass function will be calculated in the following way

i.) P(X=0) which is the probability that neither of the components meet the specifications.

ii) P(X=1) which is the probability when either of the components will meet the specifications and the other will not.

iii) P(X=2) which is the probability that both components meet the specification.

Therefore P(X = 0) = ( 1 - 0.98) × ( 1 - 0.85)  = 0.02 × 0.15  = 0.003

and,          P(X = 1)  =    (0.98 × ( 1 - 0.85)) + (( 1 - 0.98) × 0.85)

                              =   (0.98 × 0.15) + (0.02 × 0.85)

                              =   0.147 + 0.017

                              = 0.164

and finally, P(X=2) = (0.98 × 0.85)

                              = 0.833

4 0
3 years ago
Let O be an angle in quadrant III such that cos 0 = -2/5 Find the exact values of csco and tan 0.​
vivado [14]

well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus

cos(\theta)=\cfrac{\stackrel{adjacent}{-2}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - (-2)^2}=b\implies \pm\sqrt{25-4}\implies \pm\sqrt{21}=b\implies \stackrel{III~Quadrant}{-\sqrt{21}=b}

\dotfill\\\\ csc(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{-\sqrt{21}}}\implies \stackrel{\textit{rationalizing the denominator}}{-\cfrac{5}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies -\cfrac{5\sqrt{21}}{21}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{-\sqrt{21}}}{\underset{adjacent}{-2}}\implies tan(\theta)=\cfrac{\sqrt{21}}{2}

4 0
2 years ago
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