If x represents the width of the poster (including borders), the area of the finished poster can be written as
.. a = x*(390/(x -10) +8)
.. = 8x +390 +3900/(x -10)
Then the derivative with respect to x is
.. da/dx = 8 -3900/(x -10)^2
This is zero at the minimum area, where
.. x = √(3900/8) +10 ≈ 32.08 . . . . cm
The height is then
.. 390/(x -10) +8 = 8 +2√78 ≈ 25.66 . . . . cm
The poster with the smallest area is 32.08 cm wide by 25.66 cm tall.
_____
In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.
Answer:
-9/4
Step-by-step explanation:
putting these to y/x form it is 9/-10 and -9/-6 which has a difference of -9/4 (hopefully this is correct-)
The height of glass 1 is 7.6
so, you find the volume of glass 2,= 26.376
then you subtract the answer from 80 cubic cm to get the volume of glass 1
80 - 26.376 = 53.694
then you work backwards to get the height, which is 7.6
Answer:D:102
Step-by-step explanation:
Assuming Jerry calculates that if he makes a deposit of $6 each month at an APR of 4.8%, then at the end of two years the correct balance will be: $158.5
First step is to determine Jerry total deposit
over the two years
Total deposit = 24×$5
Total deposit= $144
Now let determine what the correct balance will be at end of two years
Using this formula
Maximum Amount=Principal (1+r)^t
<em>Where</em>:
Principal=$144
r=4.8%/12 = 0.4% or 0.004
t=24 months
Let plug in the formula
Maximum Balance = $144 (1.004)^24
Maximum Balance = $158.5
Based on the above calculation both Jerry $100 and Benny $163 balance are eliminated or rule out because the correct balance after two years is $158.5
Inconclusion Assuming Jerry calculates that if he makes a deposit of $6 each month at an APR of 4.8%, then at the end of two years the correct balance will be: $158.5
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