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rosijanka [135]

3 years ago

13

Solve this proportion pls

ac{x + 3}{4}" alt="\frac{x + 3}{4}" align="absmiddle" class="latex-formula"> = $\frac{7}{8}$

2 answers:

emmasim [6.3K]3 years ago

8 0

$\bf \cfrac{x+3}{4}=\cfrac{7}{8}\implies 8(x+3)=4(7)\implies 8x+24=28\implies 8x=4 \\\\\\ x=\cfrac{4}{8}\implies x=\cfrac{1}{2}$

alexandr402 [8]3 years ago

5 0

Answer:

$\large\boxed{x=\dfrac{1}{2}=0.5}$

Step-by-step explanation:

$\dfrac{x+3}{4}=\dfrac{7}{8}\qquad\text{cross multiply}\\\\8(x+3)=(4)(7)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\8x+(8)(3)=28\\\\8x+24=28\qquad\text{subtract 24 from both sides}\\\\8x+24-24=28-24\\\\8x=4\qquad\text{divide both sides by 8}\\\\\dfrac{8x}{8}=\dfrac{4}{8}\\\\x=\dfrac{4:4}{8:4}\\\\x=\dfrac{1}{2}$

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If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

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Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

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3 years ago

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