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rosijanka [135]

2 years ago

13

Solve this proportion pls

ac{x + 3}{4}" alt="\frac{x + 3}{4}" align="absmiddle" class="latex-formula"> = $\frac{7}{8}$

2 answers:

emmasim [6.3K]2 years ago

8 0

$\bf \cfrac{x+3}{4}=\cfrac{7}{8}\implies 8(x+3)=4(7)\implies 8x+24=28\implies 8x=4 \\\\\\ x=\cfrac{4}{8}\implies x=\cfrac{1}{2}$

alexandr402 [8]2 years ago

5 0

Answer:

$\large\boxed{x=\dfrac{1}{2}=0.5}$

Step-by-step explanation:

$\dfrac{x+3}{4}=\dfrac{7}{8}\qquad\text{cross multiply}\\\\8(x+3)=(4)(7)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\8x+(8)(3)=28\\\\8x+24=28\qquad\text{subtract 24 from both sides}\\\\8x+24-24=28-24\\\\8x=4\qquad\text{divide both sides by 8}\\\\\dfrac{8x}{8}=\dfrac{4}{8}\\\\x=\dfrac{4:4}{8:4}\\\\x=\dfrac{1}{2}$

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You are hiking and are trying to determine how far away the nearest cabin is, which happens to be due north from your current po

Margaret [11]

Answer:

336.7 yards away from the cabin....

Step-by-step explanation:

The angle 30.7° is also the angle of the upper interior angle of the triangle (near the cabin)

Use the tan function:

opposite = 200 yards

adjacent = x

tan(30.7°) = (opposite / adjacent)

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2 years ago

In the figure, AB || CD and mZ2 = 55°.

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Answer:

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4 0

2 years ago

A simulation was conducted using 10 fair six-sided dice, where the faces were numbered 1 through 6. respectively. All 10 dice we

kompoz [17]

Answer:

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

Step-by-step explanation:

Here, the random experiment is rolling 10, 6 faced (with faces numbered from 1 to 6) fair dice and recording the average of the numbers which comes up and the experiment is repeated 20 times.So, here sample size, n = 20 .

Let,

$X_{ij}$ = The number which comes up on the ith die on the jth trial.

∀ i = 1(1)10 and j = 1(1)20

Then,

$E(X_{ij})$ = $\frac {1 + 2 + 3 + 4 + 5 + 6}{6}$

= 3.5 ∀ i = 1(1)10 and j = 1(1)20

and,

$E(X^{2}_{ij}$ = $\frac {1^{2} + 2^{2} + 3^{2} + 4^{2} + 5^{2} + 6^{2}}{6}$

= $\frac {1 + 4 + 9 + 16 + 25 + 36}{6}$

= $\frac {91}{6}$

$\simeq$ 15.166667

so, $Var(X_{ij}$ = $(E(X^{2}_{ij} - {(E(X_{ij})}^{2})$

$\simeq 15.166667 - 3.5^{2}$

= 2.91667

and $\sigma_{X_{ij}}$ = $\sqrt {2.91667}[/tex [tex]\simeq 1.7078261036$

Now we get that,

$Y_{j} = \frac {\sum_{j = 1}^{20}X_{ij}}{20}$

We get that $Y_{j}'s$ are iid RV's ∀ j = 1(1)20

Let, ${\overline}{Y} = \frac {\sum_{j = 1}^{20}Y_{j}}{20}$

So, we get that $E({\overline}{Y}) = E(Y_{j})$

= $E(X_{ij}$ for any i = 1(1)10

= 3.5

and,

$\sigma_{({\overline}{Y})} = \frac {\sigma_{Y_{j}}}{\sqrt {20}} = \frac {\sigma_{X_{ij}}}{\sqrt {20}} = \frac {1.7078261036}{\sqrt {20}} [tex]\simeq 0.38$

Hence, the option which best describes the distribution being simulated is given by,

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

6 0

2 years ago

Please solve this <br>Solve by completing the square. 4x2+8x−3=0

Greeley [361]

Step-by-step explanation:

4x2+8x−3=0

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4x2+8x+−3=0

Step 1: Use quadratic formula with a=4, b=8, c=-3.

x=

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2a

x= −(8)±√(8)2−4(4)(−3)

2(4)

x= −8±√112

8 x=−1+

1 2 √7 or x=−1+

−1 2 √7

Answer: x=−1+

1 2√7 or x=−1+

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7 0

1 year ago