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Ainat [17]
1 year ago
14

Let's find the sizes of unknown angles in the following figures. ​

Mathematics
1 answer:
liubo4ka [24]1 year ago
8 0

Answer:

if this shape has greater that's obtuse

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1. y=4x

2. y=-7x-8

3. y=5x+63

4. y=¾x+8

5. y=-3x-½

6. y=1x-3

7. y=2

8. y=-2x+1

9. y=4x+7

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1=4(2)+b

1= 8 +b

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7=b

10. y=0

11. y=¾x+6

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<em>=¾(4)+b9</em><em> </em><em>= 3</em><em> </em><em> </em><em> </em><em>+b</em>

<em>+b-3=-3</em>

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3 years ago
Find the inverse of each function. h ( n ) = 4/n − 2
Darina [25.2K]

4(x + 2) = {h(n)}^{- 1}
7 0
3 years ago
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A quarterback throws a football to a teammate. The football is 6.5ft above the ground when it leaves the quarterback's hand. His
Elena-2011 [213]

Answer:

v=5.42m/s

Step-by-Step Explanation:

We can use conservation of energy to solve this  

mgh=1/2mv^2

2gh=v^2

v=sqrt(2gh)

v=sqrt[2*9.8m/s^2*(6.5-5)]

v=5.42m/s

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Find the exact location of all the relative and absolute extrema of the function. HINT [See Examples 1 and 2.] (Order your answe
icang [17]

Answer:

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum (or "no absolute maximum")

Step-by-step explanation:

There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.

The derivative is ...

  h'(t) = 24t^2 -48t = 24t(t -2)

This has zeros at t=0 and t=2, so that is where extremes will be located.

We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.

  h(-1) = 8(-1)²(-1-3) = -32

  h(0) = 8(0)(0-3) = 0

  h(2) = 8(2²)(2 -3) = -32

  h(∞) = 8(∞)³ = ∞

The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.

The extrema are ...

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
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_____

Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.

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3 years ago
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