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3 years ago

Write the fraction or mixed number as a decimal. Use bar notation if the decimal is a repeating decimal: 4 1/2

Mathematics

1 answer:

enyata [817]3 years ago

4 0

4.5 because 1/2 equals .5 and 4 equals for

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Please Solve so i can complete!!!!!!!! Quick Fasts

Katen [24]

I tried but couldn’t figure out sorry.

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3 years ago

A parallelogram is shown below:

Marina CMI [18]

<h3>Answer:</h3>

A: 6 ft²

B: 3 ft² is the area of each of the two congruent triangles

<h3>Step-by-step explanation:</h3>

Part A. As with a rectangle, the area of a parallelogram is the product of base length and height.

Area = (8 ft)·(3/4 ft) = 6 ft²

___

Part B. If you cut the area into two halves, each half will have half the area of the original. (That should not be a surprise.)

triangle area = (6 ft²)/2 = 3 ft²

If the triangles are created by a diagonal across the original figure, each will have a base length and height that is the same as that of the original figure. The area of a triangle is half the product of base and height, so each triangle will have area ...

triangle area = (1/2)bh = (1/2)(8 ft)(3/4 ft) = 3 ft²

5 0

3 years ago

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Eight friends ate at a restaurant and agreed to share the bill equally. Because Judi forgot her money, each of her seven friends

galina1969 [7]

Judi's share was (7 x $2.50) = $17.50 .

That was really one share out of eight.
So the total bill was

(8 x $17.50) = $140.00 .

5 0

3 years ago

5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

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3 years ago

1/2(8a+200b)<br><br> Is the answer 4a+100b?

kaheart [24]

Answer:

you are correct it is, 4a+100b

Step-by-step explanation:

4 0

2 years ago

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