Which is a discrete random variable?

-30=5(x+1) x=? Solve for X

stellarik [79]

Answer:

=-7

Step-by-step explanation:

-30=5(x+1)

-30=5x+5

-35=5x

= -7

7 0

3 years ago

Pls help me with trig :)

trapecia [35]

Answer:

Step-by-step explanation:

let ∠GEF=x

then ∠GFE=90-x

$\frac{GH}{EH}=tan x\\GH=EH~ tan x\\or~ GH=a ~tan x=6 tan x\\\frac{GH}{FH}=tan (90-x)=cot x\\GH=FH*cot x\\GH=b*cot x=27 cot x\\6 tan x=27 cotx\\\frac{tan x}{cot x}=\frac{27}{6}\\tan ^2 x=\frac{27}{6}=\frac{9}{2}\\sec^2x-tan^2x=1\\sec^2 x=1+tan ^2x=1+\frac{9}{2}=\frac{11}{2}\\\frac{EG}{EH}=sec x\\ EG=EH sec x=a sec x= 6 sec x=6\sqrt{\frac{11}{2} } =3\sqrt{22} \approx 14.07$

4 0

3 years ago

Drone INC. owns four 3D printers (D1, D2, D3, D4) that print all their Drone parts. Sometimes errors in printing occur. We know

USPshnik [31]

Answer:

Step-by-step explanation:

Hello!

There are 4 3D printers available to print drone parts, then be "Di" the event that the printer i printed the drone part (∀ i= 1,2,3,4), and the probability of a randomly selected par being print by one of them is:

D1 ⇒ P(D1)= 0.15

D2 ⇒ P(D2)= 0.25

D3 ⇒ P(D3)= 0.40

D4 ⇒ P(D4)= 0.20

Additionally, there is a chance that these printers will print defective parts. Be "Ei" represent the error rate of each print (∀ i= 1,2,3,4) then:

P(E1)= 0.01

P(E2)= 0.02

P(E3)= 0.01

P(E4)= 0.02

Ei is then the event that "the piece was printed by Di" and "the piece is defective".

You need to determine the probability of randomly selecting a defective part printed by each one of these printers, i.e. you need to find the probability of the part being printed by the i printer given that is defective, symbolically: P(DiIE)

Where "E" represents the event "the piece is defective" and its probability represents the total error rate of the production line:

P(E)= P(E1)+P(E2)+P(E3)+P(E4)= 0.01+0.02+0.01+0.02= 0.06

This is a conditional probability and you can calculate it as:

$P(A/B)= \frac{P(AnB)}{P(B)}$

To reach the asked probability, first, you need to calculate the probability of the intersection between the two events, that is, the probability of the piece being printed by the Di printer and being defective Ei.

P(D1∩E)= P(E1)= 0.01

P(D2∩E)= P(E2)= 0.02

P(D3∩E)= P(E3)= 0.01

P(D4∩E)= P(E4)= 0.02

Now you can calculate the probability of the piece bein printed by each printer given that it is defective:

$P(D1/E)= \frac{P(E1)}{P(E)} = \frac{0.01}{0.06}= 0.17$

$P(D2/E)= \frac{P(E2)}{P(E)} = \frac{0.02}{0.06}= 0.33$

$P(D3/E)= \frac{P(E3)}{P(E)} = \frac{0.01}{0.06}= 0.17$

$P(D4/E)= \frac{P(E4)}{P(E)} = \frac{0.02}{0.06}= 0.33$

P(D2)= 0.25 and P(D2/E)= 0.33 ⇒ The prior probability of D2 is smaller than the posterior probability.

The fact that P(D2) ≠ P(D2/E) means that both events are nor independent and the occurrence of the piece bein defective modifies the probability of it being printed by the second printer (D2)

I hope this helps!

8 0

3 years ago

Please help me out with this question

julsineya [31]

1) The process of cellular respiration takes place in the mitrochondria.
2) The process of photosynthesis takes place in the chloroplasts. Only plant cells and the cells of autotrophic protists and some bacteria undergo this process.
3) Phospholipids are lipids that consist of glycerol joined to two fatty acids and a phosphate group, which gives this molecule two nonpolar hydrophobic tails and a polar hydrophilic head. Phospholipids form bilayers that are used to make up biological membranes.
4)While there are definitely many more than 4 important molecules, I'm assuming the ones you are looking for are carbohydrates, proteins, Nucleic acids, and lipids.
5)A molecule is made up of two or more atoms held together by covalent bonds, whereas a compound is a substance containing two or more elements in a fixed ratio. Both molecules and compounds are made up of atoms/elements, however, compounds MUST be made up of two different kinds of elements, while molecules could consist of the same kind.

Hope this helps! :)

7 0

3 years ago

After a 16% increase the price of a pair of running shoes was $40.60. What was the old price of the shoes

Delvig [45]

Answer:

34.10

Step-by-step explanation:

Note:

16% = .16

Important:

What was the <u>old price</u> of the shoes

Solution:

40.60 x .16 = 6.946 [Round:6.50]

40.60-6.50= 34.10

Hence, the old price of the shoes is $34.10

5 0

2 years ago