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astra-53 [7]
2 years ago
6

A rectangular lot whose perimeter is 300 ft is fenced along three sides. An expensive fencing along the​ lot's length cost $30 p

er foot. An inexpensive fencing along the two side widths costs only $6 per foot. The total cost of the fencing along the three sides comes to $3690. What are the​ lot's dimensions?
Mathematics
1 answer:
puteri [66]2 years ago
6 0

The given dimensions that we have in this question are 105 and 45

<h3>How to solve for the dimensions</h3>

We have 2(l + b ) = 300

l + b = 300/2

l + b = 150 ----- 1

The fencing would be

30l + (6b + 6b) = $3690

30l + 12b = 3690 ---- 2

We have to solve this through the use of simultaneous linear equation

The calculator that has been used to solve this is the simultaneous linear equation calculator.

This would give us the values of 105 and 45.

We have to conclude that the dimensions are 105 and 45

Read more on dimensions here

brainly.com/question/19819849

#SPJ1

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I need help with this question:
SpyIntel [72]

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dimaraw [331]
The answer would be 28.
--
Here's my work:

Remember PEMDAS:
- Parentheses
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Also, remember to always go left to right.

(6+2)^2-4*3
Square everything in the parenthesis.

36+4-4*3
Multiply where you see a multiplication symbol from left to right.

36+4-12
Add.

40-12
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