A rectangular lot whose perimeter is 300 ft is fenced along three sides. An expensive fencing along the lot's length cost $30 p er foot. An inexpensive fencing along the two side widths costs only $6 per foot. The total cost of the fencing along the three sides comes to $3690. What are the lot's dimensions?
1 answer:
The given dimensions t hat we have in this question are 105 and 45
<h3>How to solve for the dimensions</h3>
We have 2(l + b ) = 300
l + b = 300/2
l + b = 150 ----- 1
The fencing would be
30l + (6b + 6b) = $3690
30l + 12b = 3690 ---- 2
We have to solve this through the use of simultaneous linear equation
The calculator that has been used to solve this is the simultaneous linear equation calculator.
This would give us the values of 105 and 45.
We have to conclude that the dimensions are 105 and 45
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Answer: a = 8
Step-by-step explanation:
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Can you please add a picture of the problem or type all the measurements and information?
Answer:
numbers are 3x,2x,5x
so 3x+2x+5x=10x=840
so x=84
so numbers are 252,168,420
Answer:
2
sorry i dont know but i think the answer is 2 I am not sure dont bleve me