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Darina [25.2K]
3 years ago
5

3. There were 567 whos in Whoville. Each who ate 814 bowls of

Mathematics
1 answer:
Rasek [7]3 years ago
6 0
All together, there were 461,538 bowls of stew eaten all together.
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Hi . how u r doing good. pls help me with these questions , I really need help
sleet_krkn [62]

Answer:

Which grade's question is this?

5 0
2 years ago
In the diagram, the measure of 1 is 55°. If line y is rotated 5° clockwise about the point of
REY [17]
A. 60 degrees is the answer
5 0
3 years ago
Read 2 more answers
Helpppppp pleaseeeeee !!!!!!!!! !!!!
Sergio [31]

Given:

The function is:

f(x)=6x-3

To find:

The inverse of the given function, then draw the graphs of function and its inverse.

Solution:

We have,

f(x)=6x-3

Step 1: Substitute f(x)=y.

y=6x-3

Step 2: Interchange x and y.

x=6y-3

Step 3: Isolate variable y.

x+3=6y

\dfrac{x+3}{6}=y

Step 4: Substitute y=g(x).

\dfrac{x+3}{6}=g(x)

Therefore, the inverse of the given function is g(x)=\dfrac{x+3}{6} and the graphs of these functions are shown below.

8 0
2 years ago
A tree that is 4 ft tall is growing at a rate of 1 ft each year a tree that is 12 feet tall is growing at a rate of 1/2 ft each
Andreyy89

Answer:

16 years

Step-by-step explanation:

Given data

For the first tree

let the expression for the height be

y=4+x--------------1

where y= the total height

          4= the initial height

          x= the number of years

For the second tree, the expression is

y=12+0.5x-------------2

Equate 1 and 2

4+x=12+0.5x

x-0.5x=12-4

0.5x= 8

x= 8/0.5

x=16

Hence it will take 16 years for both trees to have the same height

5 0
3 years ago
20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha
zaharov [31]

Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 300, p = 0.2

So

\mu = E(X) = np = 300*0.2 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is P(X \leq 51 + 0.5) = P(X \leq 51.5), which is the pvalue of Z when X = 51.5 So

Z = \frac{X - \mu}{\sigma}

Z = \frac{51.5 - 60}{6.9282}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

4 0
3 years ago
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