Answer:(X+Y)²
X²+Y² would be greater than X²-Y² since addition gives a greater result than subtraction.
X²+Y² would be greater than 2(X+Y); this is because 2(X+Y) = 2X+2Y, which will be less than X²+Y², since X>Y.
(X+Y)² = (X+Y)(X+Y). This can be simplified using the distributive property:
X(X)+X(Y)+Y(X)+Y(Y) = X²+XY+YX+Y² = X²+2XY+Y². This is greater than X²+Y².
Answer:
I'm not so sure about this one so sorry if this is wrong
Step-by-step explanation:
Answer: yes
Step-by-step explanation: