Answer: i think the answer is -45j - 9k
Step-by-step explanation:
If angle BCD measures 70° then so does angle DBC (because you have formed an isoceles triangle inside the larger ΔABC and the two legs are equal so the two angles have to be equal. So we have a two 70° angles which leaves 40° for the 3rd angle, which is ∠BDC.
Since ∠BDC and ∠ADB are supplementary (180°) - that leaves 140° for ∠ADB and is our answer
To find the slope, u need to put the equation in y = mx + b form, where m will be ur slope.
2x - 4y = 10 ... subtract 2x from both sides
-4y = -2x + 10...divide both sides by -4
y = (-2/-4)x + (-10/4)
y = 1/2x - 5/2
y = mx + b
y = (1/2)x - 5/2
the slope(m) = 1/2
Yes 12/15 can be simplified.
To simplify 12/15 find the greatest common multiple. The <span> greatest common multiple of 12/15 is 3. Now divide 12/15 by 3.
</span>
12 ÷ 3 = 4
15 ÷ 3 = 5
4/5 is the simplified version of 12/15
Answer:
maximum area will be 1058 square yards
maximum height will be 81 feet
Step-by-step explanation:
P = 2L +2W
but in this case it will be P= L+2W and P=92 yards
L+2W = 92
Solve for L , L = 92-2W
The area of rectangle A = L x W
Plug in L and simplify: A = (92-2W)W =92W -2W²
Plot in your calculator and look for maximum so when the width is 23 yards maximum area will be 1058 square yards.
Second problems is the maximum height of the rocket. Maximum will be at the vertex of the upside-down parabola.
