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3 years ago

What happens before the nucleus of the parent cell has divided into two new nuclear

1 answer:

3 0

Before I get to the answer, I would recommend that you post biology questions under the biology category. You should get your answers more quickly that way :)
There are two things that happen before a parent cell divides:
1) DNA in the nucleus of the parent cell must replicate (this happens in the S phase of the cell cycle). If you're looking for a single answer to your question, then this is probably it.
2) Also, the cell must grow and some organelles (like the mitochondria) must also replicate before the parent cell divides. If organelles like the mitochondria did not replicate, then you would eventually end up with daughter cells that don't have enough mitochondria to support themselves.

You might be interested in

Indicate whether the following balanced equations involve oxidation-reduction. Check all that apply. Check all that apply. 2H2SO

guapka [62]

Answer : The balanced equations involve oxidation-reduction are:

(a) $2H_2SO_4(aq)+2NaBr(s)\rightarrow Br_2(l)+SO_2(g)+Na_2SO_4(aq)+2H_2O(l)$

(b) $3SO_2(g)+2HNO_3(aq)+2H_2O(l)\rightarrow 3H_2SO_4(aq)+2NO(g)$

(c) $NaI(aq)+3HOCl(aq)\rightarrow NaIO_3(aq)+3HCl(aq)$

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

(a) The given chemical reaction is:

$2H_2SO_4(aq)+2NaBr(s)\rightarrow Br_2(l)+SO_2(g)+Na_2SO_4(aq)+2H_2O(l)$

This reaction involve oxidation-reduction reaction because the oxidation state bromine changes from (-1) to (0) which shows oxidation and sulfur changes from (+6) to (+4) which shows reduction.

(b) The given chemical reaction is:

$3SO_2(g)+2HNO_3(aq)+2H_2O(l)\rightarrow 3H_2SO_4(aq)+2NO(g)$

This reaction involve oxidation-reduction reaction because the oxidation state sulfur changes from (+4) to (+6) which shows oxidation and nitrogen changes from (+5) to (+2) which shows reduction.

(c) The given chemical reaction is:

$NaI(aq)+3HOCl(aq)\rightarrow NaIO_3(aq)+3HCl(aq)$

This reaction involve oxidation-reduction reaction because the oxidation state iodine changes from (-1) to (+5) which shows oxidation and chlorine changes from (+5) to (-1) which shows reduction.

(d) The given chemical reaction is:

$PBr_3(l)+3H_2O(l)\rightarrow H_3PO_3(aq)+3HBr(aq)$

This reaction does not involve oxidation-reduction reaction because the oxidation state of element present on reactant and product side are same.

3 0

3 years ago

Molarity, is the concentration of a solution expressed in terms of moles solute per liter of solution. What is the molarity of a

pishuonlain [190]

molarity of the CuSO₄ solution = 0.68 moles/L

Explanation:

The formula for molar concentration is:

molar concentration (molarity) = number of moles / solution volume (L)

number of moles = mass / molecular weight

number of moles of CuSO₄ = 12.304 / 159.6

number of moles of CuSO₄ = 0.07709 moles

molar concentration of the CuSO₄ solution = 0.07709 / 0.1127

molar concentration of the CuSO₄ solution = 0.68 moles/L

Learn more about:

molarity

brainly.com/question/13898480

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8 0

3 years ago

What is the mass (in grams) of 9.93 Ă— 1024 molecules of methanol (CH3OH)?

WINSTONCH [101]

Answer is: mass of methanol is 528.32 grams.

N(CH₃OH) = 9.93·10²⁴; number of methanol molecules.

n(CH₃OH) = N(CH₃OH) ÷ Na (Avogadro constant).

n(CH₃OH) = 9.93·10²⁴ ÷ 6.022·10²³ 1/mol.

n(CH₃OH) = 16.49 mol; amount of substance.

m(CH₃OH) = n(CH₃OH) · M(CH₃OH).

m(CH₃OH) = 16.49 mol · 32.04 g/mol.

m(CH₃OH) = 528.32 g.

7 0

3 years ago

a regular solid has a length of 28cm. , a width of 16cm. and a total surface area of 1424cm squared. What is the total surface a

Brrunno [24]

Answer:

A = 356 cm²

Explanation:

In this case, you need to use the formula to calculate the area of regular solid.

This is the following expression:

S = 2LH + 2LW + 2WH

Where:

L: length

W: Width

H: Height

But we do not know the height of the solid. We should calculate it with the given data first:

1424 = 2*28*H + 2*28*16 + 2*16*H

1424 = 56H + 896 + 32H

1424 - 896 = 88H

H = 528/88

H = 6 cm

Now that we know the height we can calculate the area of the other solid. In the other solid the length has been reduced to half, so I will assume that the Width and height is also reduced to half.

L2 = 14 cm

W2 = 8 cm

H2 = 3 cm

Replacing we have:

S = (2*14*3) + (2*14*8) + (2*8*3)

S = 356 cm²

And this should be the total surface area, assuming the width and height is reduced to half too.

If you don't assume it's reduced to half, then use the original values of Width and Height. Doing so, the Surface would be:

S = (2*14*6) + (2*14*16) + (2*6*16)

S = 808 cm²

5 0

3 years ago

PLZ HELP THIS IS DUE RN!!!!!! NO ONE IS HELPING ME :(

Juli2301 [7.4K]

Answer:

Eght: 0

Explanation:

The work formula is W = F*d where d is displacement (which means the direction matters)

Same amount of work.

Eight

Time does not matter in Work. Force and Distance do.

F = 50 N

s = 0 The only work you have done is move the ball above your head. Thereafter you just held it.

t = 15 but no work is done. Tell your tired muscles that as they try and deal with holding a 5 kg mass above you head.

W = 0

Nine

Again from the last question you should be able to tell that time does not matter. The force is the same for both of you (that's why he's your identical twin).

So the work is the same. You both weigh the same. You both went the same distance.

4 0

3 years ago