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3 years ago

What is the mass (in grams) of 9.93 Ă— 1024 molecules of methanol (CH3OH)?

Chemistry

1 answer:

WINSTONCH [101]3 years ago

7 0

Answer is: mass of methanol is 528.32 grams.

N(CH₃OH) = 9.93·10²⁴; number of methanol molecules.

n(CH₃OH) = N(CH₃OH) ÷ Na (Avogadro constant).

n(CH₃OH) = 9.93·10²⁴ ÷ 6.022·10²³ 1/mol.

n(CH₃OH) = 16.49 mol; amount of substance.

m(CH₃OH) = n(CH₃OH) · M(CH₃OH).

m(CH₃OH) = 16.49 mol · 32.04 g/mol.

m(CH₃OH) = 528.32 g.

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Vlad1618 [11]

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To balance the chemical equation the number of atoms of each element entering the reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

Bellow we have the balanced chemical equation of the complete combustion of C₃H₇OH:

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to have integer coefficients we multiply the reaction with 2:

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3 years ago

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3 years ago

At a particular temperature, 12.0 moles of so3 is placed into a 3.0-l rigid container, and the so3 dissociates by the reaction 2

saul85 [17]

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I 12 0 0
C -2x +2x +x
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E 12-2x 2x x

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