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oee [108]
3 years ago
14

a regular solid has a length of 28cm. , a width of 16cm. and a total surface area of 1424cm squared. What is the total surface a

rea of a similar rectangular solid with a length of 14cm.
Chemistry
1 answer:
Brrunno [24]3 years ago
5 0

Answer:

A = 356 cm²

Explanation:

In this case, you need to use the formula to calculate the area of  regular solid.

This is the following expression:

S = 2LH + 2LW + 2WH

Where:

L: length

W: Width

H: Height

But we do not know the height of the solid. We should calculate it with the given data first:

1424 = 2*28*H + 2*28*16 + 2*16*H

1424 = 56H + 896 + 32H

1424 - 896 = 88H

H = 528/88

<em>H = 6 cm</em>

Now that we know the height we can calculate the area of the other solid. In the other solid the length has been reduced to half, so I will assume that the Width and height is also reduced to half.

L2 = 14 cm

W2 = 8 cm

H2 = 3 cm

Replacing we have:

S = (2*14*3) + (2*14*8) + (2*8*3)

<u>S = 356 cm²</u>

<u>And this should be the total surface area, assuming the width and height is reduced to half too.</u>

If you don't assume it's reduced to half, then use the original values of Width and Height. Doing so, the Surface would be:

S = (2*14*6) + (2*14*16) + (2*6*16)

S = 808 cm²

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