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Vanyuwa [196]
2 years ago
6

Please help me with alg 2 question!

Mathematics
1 answer:
AlladinOne [14]2 years ago
3 0

Answer:

J

Step-by-step explanation:

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Wisdom scores n marks in a test. a. Antonio scores 2 marks less than wisdom. Write down an expression for Antonio's mark in term
jenyasd209 [6]
Wisdom’s score = n
Antonio’s score = n-2
8 0
3 years ago
John bought a used truck for $4,500. He made an agreement with the dealer to put $1,500 down and make payments of $350 for the n
lbvjy [14]
<span>The extra cost can be calculated by working out the total he has spent and subtracting the value of the truck. He spends $1500 on a downpayment and (350 x 10 = $3500) on monthly payments, giving him a total outlay of $5000. This means he overspent by $500. $500 interest was paid for 10 months, so at that same rate, $600 would have been paid for 12 months. $600 as a percentage of the cost of the truck minus the down payment ($3000) is 20%. </span>
4 0
3 years ago
Insert geometric means in each geometric sequence.
Digiron [165]

Answer:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

Step-by-step explanation:

Given the Geometric sequences:

1. ___, 24, ___, ___, 3/64

2. ___, 1/4, 1/2, ___

3. 81, ___, ___, ___, ___, 1/3

To find:

The values in the blanks of the given geometric sequences.

Solution:

First of all, let us learn about the n^{th} term of a geometric sequence.

a_n=ar^{n-1}

Where a is the first term and

r is the common ratio by which each term varies from the previous term.

Considering the first sequence, we are given the second and fifth terms of the sequences.

Applying the above formula:

ar = 24\\ar^4 = \dfrac{3}{64}

Solving the above equation:

r = \dfrac{1}{8}

Therefore, the sequence is:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

Considering the second given sequence:

ar = \dfrac{1}{4}\\ar^2 = \dfrac{1}{2}\\\text{Solving the above equations}, r = 2

Therefore, the sequence is:

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

Considering the third sequence:

a = 81\\ar^5=\dfrac{1}{3}\\\Rightarrow r = 3

Therefore, the sequence is:

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

5 0
3 years ago
-4x+4=6 <br> x=?<br> 2x+10=50<br> x=?<br> -3x-14=-5<br> x=?<br> 2/3x+2=5<br> x=?
Nadya [2.5K]
-4x + 4 = 6
x = -.5

2x + 10 = 50
x = 20

-3x - 14 = -5
x = -3

2/3x + 2 = 5
x = 4.5
5 0
3 years ago
Use grid paper to find the median of the data. Then find the median of the lower half and the median of the upper half of the da
loris [4]
Upper half of the data: 81 lower half of the data: 98
3 0
3 years ago
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