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Doss [256]
3 years ago
14

HELP LOOK AT PICTURE

Mathematics
1 answer:
mixas84 [53]3 years ago
6 0

Answer:

It increases.

Step-by-step explanation:

Usually putting a variable in front of a number is multiplying, and as the number your multiplying with increases, the value increases.

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ASAP!!!!!!10 POINTS I NEED HELP!!!!!!!! A beekeeper pours honey into jars. Each large jar holds 18 ounces of honey. Each small j
Sophie [7]

Answer:

1,100

Step-by-step explanation:

The total number of ounces that were put in  jars was 1,128 Oz  so your answer would be 1,110 rounded to the nearest hundred.

6 0
3 years ago
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Ok so this isn't actual homework but I need help calculating this.
jeka57 [31]
Ok so there is 60 minutes in an hour and you have 107 minutes so
107-60 = 47 ( 60 has become an hour)

So we are left with 47 minutes, so add the hour to 7:45 which will make it 8:45 pm
Then add 15 to make it 9:00 pm ( 47 - 15 = 32)

And so then add 32 minutes to 9:00 pm 

Answer is 9:32 p.m.
7 0
3 years ago
What is the answer to this fraction problem 4/5 - 8/15?
Marianna [84]
Is the answer to your question 4/15?
5 0
3 years ago
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Describe a scenario where the function value exists at x=c, but the limit does not exist.
Vikki [24]

The scenario can be described using a piecewise function like:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

<h3>When the value exists but the limit does not?</h3>

Remember that the limit only exists if the limit from left and the limit from the right give the same value.

Then, we can just define a piecewise function of the form:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

Clearly, this is not a continuous function.

Notice that:

f(c) = c.\\\\ \lim_{x \to c^{-}} f(x) = 1/c\\\\ \lim_{x \to c^{+}} f(x) = 1/(c + 73)

So the limits from left and right are different, then:

\lim_{x \to c^{}} f(x)

Does not exist.

If you want to learn more about limits:

brainly.com/question/5313449

#SPJ1

6 0
2 years ago
I need help please!!!!!!!
shusha [124]

its an obtuse angle

4 0
3 years ago
Read 2 more answers
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