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Nataly_w [17]
2 years ago
15

HELP HELP HELP HELP PLEASEEE

Mathematics
1 answer:
Sphinxa [80]2 years ago
3 0

The valid probability distributions are the ones in options C and D.

<h3>Which of the following are valid probability distributions?</h3>

For discrete random variables with probabilities p₁, p₂, ..., pₙ, there are two rules:

  • All of these probabilities are numbers between 0 and 1.
  • p₁ + p₂ + ... + pₙ = 1.

So, for the first rule we can discard the first option, where we have negative probabilities.

To check the other 4 options, just add the probabilities and see if the addition gives 1.

The options that add up to 1 are C and D, so these two are the correct options.

D: 1/5 + 1/10 + 1/10 + 1/10 + 1/5 + 1/10 + 1/10 + 1/10 = 1

C: 1/6 + 1/6 + 1/6 + 1/6 + 1/6 + 1/6 = 1

If you want to learn more about probability:

brainly.com/question/25870256

#SPJ1

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Sum of three numbers in an as is 33 and the sum of thier cubes is 5049.find the numbers
Alex73 [517]

Sum of three numbers is 33 and  sum of their cubes is 5049 then three numbers are 7,11,15 or 15,11,7.

As given,

Let a-d, a, a +d be three numbers

Sum =33

⇒a-d + a +a +d =33

⇒ a =11

Sum of cubes= 5049

⇒ (a-d)³ + a +(a +d)³ =5049

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⇒3a³ + 6ad² = 5049

⇒ d=± 4

Therefore, sum of three numbers is 33 and  sum of their cubes is 5049 then three numbers are 7,11,15 or 15,11,7.

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