Answer:
-6 is the answer
Step-by-step explanation:
<span>To solve a triangle using law of sines you must have the length of one side and the measure of the angle opposite that particular side. Then you must have one other piece of information, either one more side length or one more angle measurement. However in some cases when the information you are given is two consecutive sides, and the angle is not between the two consecutive sides, then there exists the possibility that there are two different triangles that will satisfy the given information.</span>
Answer:
Length = 6
Width = 5.5
Step-by-step explanation:
Let's use the variable x to represent the width:
x = width
The question says that the length of the rectangle is "5 ft less than double the width". This length can be represented like this:
2x - 5 = length
To find the area of a rectangle, you multiply the width and length, so we are going to write an equation where we multiply the width and length and set it equal to 33 ft^2, which is the area:
(x)(2x - 5) = 33
Now use basic algebra to solve for x:
2x^2 - 5x = 33
2x^2 - 5x - 33 = 0
2x^2 + 6x - 11x - 33 = 0
(2x^2 + 6x) + (-11x - 33) = 0
2x(x + 3) - 11(x + 3) = 0
(2x - 11) (x + 3) = 0
x = 11/2, -3
x either equals 11/2 or -3. However, remember that x represents the width, and you can't have a negative number for a width, so x = 11/2 or 5.5.
Now plug in 5.5 to the length expression and simplify:
2(5.5) - 5
11 - 5 = 6
The length is 6 and the width is 5.5.
Hope this helps (●'◡'●)
