Answer:
I think it is the 3rd one
Step-by-step explanation:
I hope it is. Sorry if not, I tried.
First I would change the descriptions of the numbers into expressions.
first number is n
second number is n + 6
third number is 4n (4 x n)
Then you would insert these expressions into an equation and isolate n.
n + n + 6 + 4n = 144
n + n + 4n = 144 - 6
6n = 138
n = 138/6
n = 23
Lastly, you would plug in this value into all of the expressions.
first number is 23
second number is 23 + 6 = 29
third number is 4(23) = 92
Therefore, the numbers are 23, 29, and 92.
Answer:
-$13.5
Step-by-step explanation:
Let x be a random variable of a count of player gain.
- We are told that if the die shows 3, the player wins $45.
- there is a charge of $9 to play the game
If he wins, he gains; 45 - 9 = $36
If he looses, he has a net gain which is a loss = -$9
Thus, the x-values are; (36, -9)
Probability of getting a 3 which is a win is P(X) = 1/6 since there are 6 numbers on the dice and probability of getting any other number is P(X) = 5/6
Thus;
E(X) = Σ(x•P(X)) = (1/6)(36) + (5/6)(-9)
E(X) = (1/6)(36 - (5 × 9))
E(X) = (1/6)(36 - 45)
E(X) = -9/6 = -3/2
E(X) = -3/2
This represents -3/2 of $9 = -(3/2) × 9 = - 27/2 = -$13.5
Answer:
8 u ocho
¡Espero que ayude!
Step-by-step explanation:
