Reaction B has a higher activation energy than reaction A.
The correct answer for the question that is being presented above is this one: "Electrovalency is characterized with the transferring of one or more electrons from one atom to another together with the formation of ions and as well as the number of positive and negative charges.
The Lewis and Langmuir theory of electrovalency (and as well as Kossel's) is dealing with Ionic bonds.
Lewis: electron-pair sharing, octet rule, Lewis Symbols or StructureLangmuir: introduced term "covalent" bond, and popularized Lewis's ideas
The Lewis-Langmuir electron-pair or covalent bond is referred as the homopolar bond, where the complete transfer of electrons give rise to ionic, or electrovalent bond (1) through attraction of opposite charges.
OH is a polyatomic ion, meaning it is a covalently bonded set of two or more atoms (in this case Oxygen and Hydrogen). When there is more than one mole or atom of an ion present in a formula, polyatomic ions are written in parentheses to show that they are bonded and the subscript is used to show that there are multiple of that bonded ion present. OH is Hydroxide, which consists of Oxygen and Hydrogen, so yes there are two of each element in the formula but because they are bonded to form Hydroxide, OH is in parentheses, therefore Ca(OH)2 is the correct formula.
(in short it is Ca(OH)2 because OH is a bonded ion)
Answer:
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the acidic buffer solution as:
Given that:-
[Acid] = 0.12 M
Volume = 3.0 L
pKa = 3.74
pH = 5.30
So,
Solving, we get that:-
[Sodium formate] = 4.36 M
Considering:
So,
So, Moles of sodium formate = 4.36*3.0 moles = 13.08 moles
Molar mass of sodium formate = 68.01 g/mol
The formula for the calculation of moles is shown below:
Thus,