The state in which the forward reaction rate and the reverse reaction rate are equal. Th concentration of chemicals don’t change
Hello!
First, HNO₃ dissociates in the following way:
HNO₃(aq) → H⁺(aq) + NO₃⁻(aq)
Next, there is a neutralization reaction with Methylamine:
H⁺(aq) + CH₃NH₂(aq) → CH₃NH₃⁺(aq)
Finally, the formed methylammonium ion weakly dissociates in the following way:
CH₃NH₃⁺(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CH₃NH₂ (aq)
From this sequence of reactions, we can see that the resulting solution would be slightly more acidic than the initial one, as the buffer solution resists the addition of strong acid.
Have a nice day!
Answer:
Empirical formula is C₃H₃O
Explanation:
Given data:
Mass of ethyl butyrate = 1.95 mg
Mass of CO₂ = 4.42 mg
Mass of water = 1.81 mg
Empirical formula = ?
Solution:
Percentage of C = 4.42/1.95 × 12/44×100
= 2.27× 0.273 ×100
= 62
percentage of H = 1.81/1.95 × 2/18 × 100
= 0.93 × 0.11 ×100
= 10.23
percentage of oxygen = 100 - (72.23)
= 27.77
number of gram atoms of C = 62/12 =5.17
number of gram atoms of H = 10.23 / 2 =5.115
number of gram atoms of O = 27.77 / 16 =1.74
Atomic ratio:
C : H : O
5.17/1.74 : 5.115/1.74 : 1.74/1.74
3 : 3 : 1
Empirical formula is C₃H₃O
The answer to your question is true
Answer:
How does the equilibrium change with the removal of hydrogen (H2) gas from this equation? 2H2S ⇌ 2H2(g) + S2(g) A. ... Equilibrium shifts left to produce less reactant.
Explanation:
option A is the correct answer
Equilibrium shifts right to produce more product.
I hope it will help you.