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salantis [7]
3 years ago
10

Which of the following is a chemical property of apples?

Chemistry
1 answer:
Nesterboy [21]3 years ago
4 0
Apples turnjng brown when left in air
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Explanation:

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How do properties of water break down rocks?
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Freezing water can break rock without any change in the minerals that form the rock (physical weathering). This usually produces small particles and sand. Water with dissolved gases and other chemicals causes the minerals in rocks to be changed, leading to the deterioration of the rock (chemical weathering).

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const2013 [10]

Answer:

it is formed by covalent bonds. the oxygen atom shares one elctron with each chlorine atom, forming single covalent bonds ( cl — o — cl )

6 0
3 years ago
How long of time in hours will it take to plate out 1.0 kg Ni from aqueous Ni2+ solution, if the electrical current is 102 A? wh
netineya [11]

Answer: 8.95 hours

Explanation:

Ni^{2+}+2e^-\rightarrow Ni

96500\times 2=193000 Coloumb of electricity deposits 1 mole of Nickel

1 mole of Nickel weighs = 58.7 g

Given quantity = 1.0 kg = 1000 g  (1kg=1000g)

58.7 g of Nickel is deposited by 193000 C of electricity

1000 g of Nickel is deposited by =\frac{193000}{58.7}\times 1000=3287904.6C  of electricity

Q=I\times t

where Q= quantity of electricity in coloumbs  = 3287904.6C

I = current in amperes = 102 A

t= time in seconds = ?

3287904.6C=102A\times t

t=32234.359sec

t=8.95hr      (1h=3600 sec)

Thus 8.95 hours it takes to plate out 1.0 kg Ni from aqueous Ni^{2+} solution, if the electrical current is 102 A.

4 0
3 years ago
Find the solubility of agi in 2.5 m nh3 [ksp of agi = 8.3 × 10−17; kf of ag(nh3)2+ = 1.7 × 107].
vovangra [49]
When the first reaction equation is:

AgI(S) ↔ Ag+(Aq)  +  I-(Aq)

So, the Ksp expression = [Ag+][I-]

∴Ksp = [Ag+][I-] = 8.3 x 10^-17

Then the second reaction equation is:

 Ag+(aq)  + 2NH3(aq) ↔  Ag(NH3)2+  

So, Kf expression = [Ag(NH3)2+] / [Ag+] [NH3]^2

∴Kf = [Ag(NH3)2+] /[Ag+] [NH3]^2 = 1.7 x 10^7

by combining the two equations and solve for Ag+:

and by using ICE table:

               AgI(aq) + 2NH3  ↔  Ag(NH3)2+  + I-
initial                        2.5                    0            0 

change                    -2X                    +X             +X

Equ                     (2.5-2X)                   X               X

so K = [Ag(NH3)2+] [I-] / [NH3]^2

Kf * Ksp = X^2 / (2.5-2X)

8.3 x 10^-17 * 1.7 x10^7 = X^2 / (2.5-2X) by solving for X

∴ X = 5.9 x 10^-5 

∴ the solubility of AgI = X = 5.9 x 10^-5 M

4 0
3 years ago
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