Given the relationship T^2 = A^3, to compare the values of the orbital periods of X and Y, it would be easier to assign values. Since the Planet Y's distance A is twice that of Planet X's distance A, this can be shown below:
For Planet X (where A = 2):
T^2 = 2^3
T = 2.828
For Planet Y (where A = 4)
T^2 = 4^3
T = 8
Therefore, planet Y's orbital period is larger by (8/2.828) = 2.83 times.
Answer:
idk either :) cuz i nver care about it :3
If you work out the fraction of 1600 that 640 you can apply this to the number of 6s, that she based this off of.
640÷1600=0.4
To calculate the number of times she rolled the dice you do 8÷0.4=20.
Therefore she rolled the cube 20 times to get 8 6s.
Answer:
46.16 years
Step-by-step explanation:
(correct equation with missing symbols: h = 62.5 * (^3√t) + 75.8)
To find the age of an elephant that has a shoulder height of 300 centimeters, we just need to use the value of h = 300 in the equation, and then find the value of t:
h = 62.5 * (^3√t) + 75.8
300 = 62.5 * (^3√t) + 75.8
62.5 * (^3√t) = 224.2
^3√t = 3.5872
t = 3.5872^3 = 46.16 years
The age of the elephant is 46.16 years.
Answer:
a=7
Step-by-step explanation:
6a-42=-7a+49
(add 7a to 6a)
13a-42=49
(add 42 to 49)
13a=91
(divide 91 by 13)
a=7