We let x the distance traveled by Car A and y the distance traveled by car B. The speed of car A can be represented as x/2.4 and for Car B is y/4. From the statement given, we can write an equation relating the speed of both cars.
x/2.4 = 22 + y/4
Since y = x, then:
x/2.4 = 22 + x/4
Solving for x, we obtain:
x= 132 meters traveled by both cars
Therefore, Car A has a speed of 55 mph.
Answer:
2x^4 − y
6 + w
z + 1
Step-by-step explanation:
Answer:
The correct option is C.
Step-by-step explanation:
The given equation is

It can be rewritten as
.....(1)
The standard form of an ellipse is
....(2)
Where (h,k) is center of the ellipse.
If a>b, then the vertices of the ellipse are
.
From (1) and (2) we get

Since a>b, therefore the vertices of the ellipse are


The vertices of the given ellipse are (10, –7) and (2, –7). Therefore the correct option is C.
Answer:
![\large\boxed{\ln\sqrt[3]{e^4}=\dfrac{4}{3}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Cln%5Csqrt%5B3%5D%7Be%5E4%7D%3D%5Cdfrac%7B4%7D%7B3%7D%7D)
Step-by-step explanation:
![\text{Use}\\\\\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\ln a^n=n\ln a\\\\\ln e=1\\-----------\\\\\ln\sqrt[3]{e^4}=\ln e^\frac{4}{3}=\dfrac{4}{3}\ln e=\dfrac{4}{3}\cdot1=\dfrac{4}{3}](https://tex.z-dn.net/?f=%5Ctext%7BUse%7D%5C%5C%5C%5C%5Csqrt%5Bn%5D%7Ba%5Em%7D%3Da%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C%5Cln%20a%5En%3Dn%5Cln%20a%5C%5C%5C%5C%5Cln%20e%3D1%5C%5C-----------%5C%5C%5C%5C%5Cln%5Csqrt%5B3%5D%7Be%5E4%7D%3D%5Cln%20e%5E%5Cfrac%7B4%7D%7B3%7D%3D%5Cdfrac%7B4%7D%7B3%7D%5Cln%20e%3D%5Cdfrac%7B4%7D%7B3%7D%5Ccdot1%3D%5Cdfrac%7B4%7D%7B3%7D)
Answer: y = -1,2x + 3.4
Step-by-step explanation:
y = ax + b
(2,1) => 1 = 2a + b (1)
(17,-17) => -17 =17a + b (2)
Using caculator Mode => 5 =>1
We get : a=- 1.2 , b = 3.4
=> y = -1.2x + 3.4