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2 years ago

I need help its not 4236

Mathematics

1 answer:

Oduvanchick [21]2 years ago

7 0

Answer: 4236

Step-by-step explanation: I used a calculator. If it's wrong, tell your teacher/instructor.

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The sum of a number and twenty-one is sixty-four. what is the value of the number?

Alchen [17]

The values of the number is 43

x+21=64

subtract 21 on each side

x = 43

5 0

2 years ago

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Complete the equation of the line through ( 4 , -8 ) and ( 8 , 5 )

irinina [24]

Answer:

Therefore the equation of the line through ( 4 , -8 ) and ( 8 , 5 ) is

13x - 4y = 84.

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( 4 ,-8)

point B( x₂ , y₂) ≡ (8 , 5)

To Find:

Equation of Line AB =?

Solution:

Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula

$(y - y_{1} )=(\frac{y_{2}-y_{1} }{x_{2}-x_{1} })\times(x-x_{1}) \\$

Substituting the given values in a above equation we get

$(y-(-8))=(\frac{5-(8)}{8-4})\times (x-4)\\ \\(y+8)=\frac{13}{4}(x-4)\\\\4(y+8)=13(x-4)\\4y+32=13x-52\\13x-4y=84...............\textrm{which is the required equation of the line AB}$

Therefore the equation of the line through ( 4 , -8 ) and ( 8 , 5 ) is

13x - 4y = 84.

4 0

3 years ago

What is the solution to the equation below?

Alekssandra [29.7K]

Answer :

It is D because you have to subtract 4.73 from both sides in order to isolate the y by itself and get the answer which is 3.27

Step-by-step explanation:

3 0

2 years ago

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Which number line shows point A at 3, point B at −1.5, point C at , and point D, which is the opposite of point A?

Oduvanchick [21]

Step-by-step explanation:

We have that point A is at 3.

This is 3 units to the right of 0 on the number line.

The point that is opposite of A should be 3 units to the left of 0.

That point will be at -3.

Therefore you have to choose the point that is on -3.

It should be similar to one in the attachment.

6 0

3 years ago

Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F

Svet_ta [14]

Answer:

$A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36$

Step-by-step explanation:

The equations are:

$y = x^{2} + 2x + 3$

$y = 2x + 12$

The two graphs intersect when:

$x^{2} + 2x + 3 = 2x + 12$

$x^{2} = 0$

$x_{1} = 3\\x_{2} = -3$

To find the area under the curve for the first equation:

$A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

To find the area under the curve for the second equation:

$A_{2} = \int\limits^3__-3}{2x + 12} \, dx$

To find the total area:

$A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

Simplifying the equation:

$A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx$

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).

3 0

3 years ago