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2 years ago

Could somone help me on this MAD question

Mathematics

1 answer:

olga_2 [115]2 years ago

3 0

The mean absolute deviation of the set of numbers is 5/4

<h3>How to determine the mean absolute deviation?</h3>

The set of numbers is given as:

1 1/2, 0, 4 and 2 1/2

Rewrite the set of numbers as:

1.5, 0, 4 and 2.5

Calculate the mean of the set using:

$\bar x$ = Sum/Count

So, we have:

$\bar x$ = (1.5 + 0 + 4 + 2.5)/4

Evaluate

$\bar x$ = 2

The mean absolute deviation is then calculated as:

M.A.D = 1/n * ∑|x - $\bar x$ |

So, we have:

M.A.D = 1/4 * [|1.5 - 2| + |0 - 2| + |4 - 2| + |2.5 - 2|]

Evaluate the absolute difference

M.A.D = 1/4 * [0.5 + 2 + 2 + 0.5]

Evaluate the sum

M.A.D = 1/4 * 5

Evaluate the product

M.A.D = 5/4

Hence, the mean absolute deviation of the set of numbers is 5/4

Read more about mean absolute deviation at

brainly.com/question/9495630

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Anon25 [30]

Answer:

B is the only one i know, sorry.

Step-by-step explanation:

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8 0

3 years ago

Help if you can PLease

cricket20 [7]

Answer:

x = 2

Step-by-step explanation:

all the angles in a triangle that are added together will equal 180 degrees

so having known that you will get this equation: \/

2x+5+8x=25

then you solve

8x+2x+5=25

10x+5=25

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4 0

3 years ago

Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if:a) a

lara31 [8.8K]

Answer:

A) 0.0009765625

B) 0.0060466176

C) 2.7756 x 10^(-17)

Step-by-step explanation:

A) This problem follows a binomial distribution. The number of successes among a fixed number of trials is; n = 10

If a 0 bit and 1 bit are equally likely, then the probability to select in 1 bit is; p = 1/2 = 0.5

Now the definition of binomial probability is given by;

P(K = x) = C(n, k)•p^(k)•(1 - p)^(n - k)

Now, we want the definition of this probability at k = 10.

Thus;

P(x = 10) = C(10,10)•0.5^(10)•(1 - 0.5)^(10 - 10)

P(x = 10) = 0.0009765625

B) here we are given that p = 0.6 while n remains 10 and k = 10

Thus;

P(x = 10) = C(10,10)•0.6^(10)•(1 - 0.6)^(10 - 10)

P(x=10) = 0.0060466176

C) we are given that;

P((x_i) = 1) = 1/(2^(i))

Where i = 1,2,3.....,n

Now, the probability for the different bits is independent, so we can use multiplication rule for independent events which gives;

P(x = 10) = P((x_1) = 1)•P((x_2) = 1)•P((x_3) = 1)••P((x_4) = 1)•P((x_5) = 1)•P((x_6) = 1)•P((x_7) = 1)•P((x_8) = 1)•P((x_9) = 1)•P((x_10) = 1)

This gives;

P(x = 10) = [1/(2^(1))]•[1/(2^(2))]•[1/(2^(3))]•[1/(2^(4))]....•[1/(2^(10))]

This gives;

P(x = 10) = [1/(2^(55))]

P(x = 10) = 2.7756 x 10^(-17)

3 0

3 years ago

Por favor responder a esta pregunta

ahrayia [7]

Por determinante:
5...1...1
1...0...1 = 0 --> se o determinante for igual a 0, os pontos estarão alinhados.
3...3...1

calculando: (5 x 0 x 1 + 1 x 1 x 3 + 1 x 3 x 1) - (1 x 0 x 3 + 1 x 1 x 1 + 3 x 1 x 5) =
0 + 3 + 3 - 0 - 1 - 15 =
6 - 1 - 15 =
5 - 15 = - 10 --> como não deu zero, os pontos não estão alinhados.

4 0

3 years ago

Triangle ABC is congruent to A'BC' by the HL theorem What single rigid transformation maps ABC onto A'BC'?

larisa [96]

Answer:

b. reflection

Step-by-step explanation:

just took the test

4 0

3 years ago

Read 2 more answers