7, 13, 19 and 25 have a common difference: 6.
6 added to 7 gives us 13; 6 added to 13 gives us 19, and so on.
Explicit formula: a(n) = 7 + 6(n-1), where 7 is the first term and n is the counter (1, 2, 3, ...).
The first term is 7 (given). This corresponds to n=1.
The second term is a(2) = 7 + 6(2-1), or 7 + 6, or 13. This corresponds to n = 2.
and so on.
Answer:
Step-by-step explanation:
Isolate the term of x and y from one side of the equation.
<h3>y=-4x-9 and y=-4x-1</h3>
First, you have to substitute of y=-4x-1.
![\Longrightarrow: \sf{[-4x-1=-4x-9]}](https://tex.z-dn.net/?f=%5CLongrightarrow%3A%20%5Csf%7B%5B-4x-1%3D-4x-9%5D%7D)
<u>Add by 4x from both sides.</u>
<u>Solve.</u>
- <u>Therefore, the correct answer is "D. No solution".</u>
I hope this helps. Let me know if you have any questions.
Point slope form:
y+9=6(x-5)
Answer:
83
Step-by-step explanation:
Let the number of robbers be x
If they share 6 rolls each, the tota rolls will be 6x and since they have five remainder, the overall total is then 6x+5
In case they share 7 rolls each, it means they have 7x rolls but here they will be less 8 rolls hence 7x-8 is the overall total.
Equating these two
7x-8=6x+5
Arranging similar terms
7x-6x=8+5
x=13
Therefore, the robbers are 13
The rolla they have will be
6(13)+5=83
Or
7(13)-8=83
Answer:
Step-by-step explanation:
1. Find two numbers that add to make the coefficient of x (in this case, -5) and that multiply to make the constant term multiplied by the coefficient of x^2 (in this case, -2 x 3 = -6)
Two numbers that work are -6 and +1
-6 x +1 = -6
-6 + -1 = -5
2. Split the middle term into the two numbers that you found.
3x^2 -6x +x -2 = 0
I've put the -6 on the left side because in our next step, when we factorise, it will be easier than having the numbers the other way around.
3. Factorise the left side by taking out common factors from each pair. The pairs I'm talking about here are '3x^2 and -6x', and 'x and -2'
3x (x-2) +1 (x-2) = 0
4. You now have two numbers both being multiplied by the term x-2. We can rearrange this equation to give us two brackets being multiplied by each other.
(3x + 1) (x-2) = 0
5. According to the Null Factor Law, if two terms are multiplied together and the result is 0, then one of those terms must be 0. Make both terms equal to 0 and solve each for x.
3x + 1 = 0 x-2 = 0
3x = -1 x = 2
x = -1/3
6. The solutions to this equation are x = 2 and x = -1/3
