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2 years ago

Determine the qualities of the given set. (select all that apply. ){(x, y) | x > 0, y > 0}

Mathematics

1 answer:

Talja [164]2 years ago

6 0

The qualities of the set {(x,y): x>0,y>0} is as under:

All points lie in first quadrant.
All values are positive and greater than zero.

Given a set {(x,y),x>0,y>0}.

We are required to determine the qualities of the set.

We know that a set is a collection of things,numbers, fractions, etc.

In any set the values of x represents the domain of the function and the values of y represents the value of codomain of the function with which the set belongs to.

Set={(x,y): x>0,y>0}

From the above set we can find the qualities stated below:

All points lie in first quadrant as the first quadrant only contains positive values of x and y.
All values are positive because it is given that they are greater than zero

Hence the qualities of the set {(x,y): x>0,y>0} are that all values should be in first quadrant and all the values are positive.

Learn more about sets at brainly.com/question/2166579

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Two 6-sided dice are tossed. One die is red and the other is white, so that they are distinguishable. (That is, we consider the

Darina [25.2K]

Answer:

Given the following events and its elements when two 6-sided dice are tossed:

A: the sum of the dice is even

B: at least one die shows a 3

C: the sum of the dice is 7

The elements of the intersections are:

a) A∩B={(1, 3),(3, 1),(3, 3),(3, 5),(5, 3)}

b) B^c∩C={(1, 6),(2, 5),(5, 2),(6, 1)}

c) A∩C={∅}

d) A^c∩B^c∩C^c={(1, 2),(1, 4),(2, 1),(4, 1),(4, 5),(5, 4),(5, 6),(6, 5)}

Step-by-step explanation:

The total number of elements of the universal set (U) for this problem is 36 elements because the number of possible combinations is 6*6.

For the event A, half of the elements satisfy the condition of the sum being an even number.

A={(1, 1),(1, 3),(1, 5),...,(6, 2),(6, 4),(6, 6)}=18 elements

For event B, the elements that contain a 3 are:

B={(1, 3),(2, 3),(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),

(4, 3),(5, 3),(6, 3)}= 11 elements

For event C, the sum of the elements is 7:

C={(1, 6),(2, 5),(3, 4),(4, 3),(5, 2),(6, 1)}=6 elements

Now let's find the intersections:

a) A∩B are the elements of A that have a 3.

A∩B={(1, 3),(3, 1),(3, 3),(3, 5),(5, 3)}

b) B^c∩C are the elements of the universal set (U) that do not have a 3 and that the sum of the dice is 7

B^c∩C={(1, 6),(2, 5),(5, 2),(6, 1)}

c) A∩C are the elements of that sum 7, but this is not possible given that all the elements of A sum an even number and 7 is not an even number.

A∩C={∅}

d) A^c∩B^c∩C^c are the elements that don't sum an even number, don't have a 3 and the sum is not 7.

A^c∩B^c∩C^c={(1, 2),(1, 4),(2, 1),(4, 1),(4, 5),(5, 4),(5, 6),(6, 5)}

5 0

3 years ago

A baby elephant can weigh 170 pounds at birth. Approximately how many kilograms is this?

Gnom [1K]

Answer:

77.1107

Step-by-step explanation:

for an approximate result, divide the mass value by 2.205

hopefully this help's

7 0

4 years ago

Read 2 more answers

Suppose i pick a jelly bean at random from a box containing two red and ten blue ones. i record the color and put the jelly bean

gtnhenbr [62]

The probability of picking a blue jelly bean is 10/12=0.833, since there are 10 blue and 12 jelly beans in total.

Each time the probability of picking blue is the same, since put back in the box whatever jelly bean we pick

P(blue, blue, blue) = P(blue) × P(blue) × P(blue) = 0.833×0.833×0.833=0.579

Answer: 0.579

8 0

4 years ago

Which answer shows this equation written in standard form?

Iteru [2.4K]

So first we solve and simplify
pemdas
first parenthasees

9-4(x-y)=-6x+6
distribute using distributeive property of multiplication which is a(b+c)=(ab)+(ac)

so -4(x-y)=-4x+4y

9-4x+4y=-6x+6
add 6x to both sides
9+2x+4y=6
subtract 9 from both sides
2x+4y=-3
only B matches this
B is the correct answer

(I don't know what standard form is but I know what simplified is)

5 0

3 years ago

Aiko stands 5 m from a tree. At that distance, the angle of elevation from the ground to the top of the tree is 80°.

denis23 [38]

Answer:

$\boxed {\boxed {\sf About \ 28.36 \ meters }}$

Step-by-step explanation:

Assuming the tree is perpendicular to the ground, we can use the right triangle trigonometric ratios to find the tree's height.

sin(θ)= opposite/hypotenuse
cos(θ)= adjacent/hypotenuse
tan(θ)= opposite/adjacent

Now, let's draw a diagram. We know Aiko is 5 meters from the base of the tree. From there, the angle to the top of the tree is 80 degrees. We are looking for x, the tree's height. The diagram attached is not to scale.

We base the sides off of the angle. x is opposite of 80 degrees and 5 is adjacent. Therefore we must use tangent.

$tan(\Theta)=\frac{opposite}{adjacent}$