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Sloan [31]
2 years ago
15

Prior to a major outbreak of e. coli o157:h7 from hamburgers, the meat inspector's primary tools were:_____.

Chemistry
1 answer:
ser-zykov [4K]2 years ago
6 0

The principal equipment of the meat inspector before a significant E. coli O157:h7 outbreak linked to hamburgers was a sharp knife.

<h3>What is E. coli?</h3>

Escherichia coli (E. coli) is a type of bacterium that ordinarily dwells in both human and animal intestines. But some strains of E. coli, most notably E. coli O157:H7, can result in intestinal infection. After the toxin they generate, E. coli O157:H7 and other strains that cause intestinal illness are known as Shiga toxin-producing E. coli (STEC). Many patients who have an E. coli infection recover completely. However, it may result in serious, even fatal, problems. These problems are more likely to occur in older adults, pregnant women, young children, and people with compromised immune systems.

To know more about E. coli, visit:

brainly.com/question/1657681

#SPJ4

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A container of hydrogen gas has the same temperature as a container of oxygen gas. The gas atoms having the greater average kine
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What is the empirical formula for a substance that is composed of 40.66% carbon, 8.53% Hydrogen,23.72% Nitrogen, and 27.09% Oxyg
prohojiy [21]

Answer:

THE EMPIRICAL FORMULA OF THE SUBSTANCE IS C2H5NO

Explanation:

The steps involved in calculating the empirical formula of this substance in shown in the table below:

Element                            Carbon           Hydrogen          Nitrogen         Oxygen

1. % Composition              40.66              8.53                 23.72                27.09

2. Mole ratio =

%mass/ atomic mass       40.66/12         8.53/1          23.72/14            27.09/16

                                       =  3.3883            8.53              1,6943             1.6931

3. Divide by smallest

value (0.6931)          3.3883/1.6931    8.53/1.6931    1.6943/1.6931   1.6931/1.6931

                               =      2.001                  5.038           1.0007                      1

4. Whole number ratio        2                       5                   1                               1

The empirical formula = C2H5NO

7 0
3 years ago
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