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2 years ago

A community consists of all the organisms in an ecosystem that belong to the same species.

Chemistry

2 answers:

kondor19780726 [428]2 years ago

6 0

The answer is false ok bye

choli [55]2 years ago

3 0

Answer:

False

Explanation:

A community consists of all the organisms in an ecosystem that belong to the same species. Population density occurs when two or more organisms seek the same resource at the same time. A carrying capacity is anything that restricts the number of individuals in a population.

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What term describes isotopes with an unbalanced number of neutrons?

MAVERICK [17]

It might be radioactive

5 0

3 years ago

2. How many moles are there in 20 grams of Carbon?

faust18 [17]

Answer:

1.6666666666666 is the ans bcz in each mole there r 12 grams of carbon so the ans is goingtobe 20÷12

3 0

2 years ago

Many repeating, simple subunits are joined together. What is the most likely

Hatshy [7]

Answer:

O a polymer

Explanation:

When many repeating simple subunits are joined together, this results into a polymer.

The simplest unit or smallest unit of any substance is called a monomer. When many units of a monomer joins together, a polymer results.

For proteins, the monomeric unit is amino-acid.
When they combine they form longer chain molecules called proteins.
For carbohydrates, the monomeric unit is called glucose.
When they are combined they give us a wide range of carbohydrate molecules.

6 0

3 years ago

Write the chemical symbol for three different atoms or atomic cations with 22 electrons

damaskus [11]

Answer:

Explanation:

To write the chemical symbol for an atom or cation with 22 electrons, we must understand some few things about an atom.

An atom is made up of positively charged paticles called protons which are located in the nucleus. The neutrons do not have any charges and are they reside together in the nucleus with the protons.

Electrons are negatively charged particles which orbits the nucleus.

Titanium in its neutral state is the 22nd element on the periodic table and it has 22 electrons.

Vanadium is the the 23rd element on the periodic table. If it loses an electron, it becomes positively charged and it is a cation.

Chromium is the 24th element on the periodic table. A loss of two electrons makes the net electrons remaining on it 22.

The symbols are:

₂₂Ti

₂₃V¹⁺

₂₄Cr²⁺

6 0

3 years ago

We want to calculate the concentrations of all species in a 0.58 M Na 2 SO 3 (sodium sulfite) solution. The ionization constants

NeX [460]

Explanation:

Reaction equation is as follows.

$Na_{2}SO_{3}(s) \rightarrow 2Na^{+}(aq) + SO^{2-}_{3}(aq)$

Here, 1 mole of $Na_{2}SO_{3}$ produces 2 moles of cations.

$[Na^{+}] = 2[Na_{2}SO_{3}] = 2 \times 0.58$

= 1.16 M

$[SO^{2-}_{3}] = [Na_{2}SO_{3}]$ = 0.58 M

The sulphite anion will act as a base and react with $H_{2}O$ to form $HSO^{-}_{3}$ and $OH^{-}$ .

As, $K_{b} = \frac{K_{w}}{K_{a_{2}}}$

= $\frac{10^{-14}}{6.3 \times 10^{-8}}$

= $1.59 \times 10^{-7}$

According to the ICE table for the given reaction,

$SO^{2-}_{3} + H_{2}O \rightleftharpoons HSO^{-}_{3} + OH^{-}$

Initial: 0.58 0 0

Change: -x +x +x

Equilibrium: 0.58 - x x x

So,

$K_{b} = \frac{[HSO^{-}_{3}][OH^{-}]}{[SO^{2-}_{3}]}$

$1.59 \times 10^{-7} = \frac{x^{2}}{0.58 - x}$

$x^{2} = 1.59 \times 10^{-7} \times (0.58 - x)$

x = 0.0003 M

So, x = $[HSO^{-}_{3}] = [OH^{-}]$ = 0.0003 M

$[SO^{2-}_{3}]$ = 0.58 - 0.0003

= 0.579 M

Now, we will use $[HSO^{-}_{3}]$ = 0.0003 M

The reaction will be as follows.

$HSO^{2-}_{3} + H_{2}O \rightleftharpoons H_{2}SO_{3} + OH^{-}$

Initial: 0.0003

Equilibrium: 0.0003 - x x x

$K_{b} = \frac{x^{2}}{0.0003 - x}$

$K_{b} = \frac{K_{w}}{K_{a_{1}}}$

= $\frac{10^{-14}}{1.4 \times 10^{-2}}$

= $7.14 \times 10^{-13}$

Therefore, $7.14 \times 10^{-13} = \frac{x^{2}}{0.0003 - x}$

As, x <<<< 0.0003. So, we can neglect x.

Therefore, $x^{2} = 7.14 \times 10^{-13} \times 0.0003$

= $0.00214 \times 10^{-13}$

x = $0.0146 \times 10^{-6}$

x = $[OH^{-}] = [H_{2}SO_{3}]$ = $1.46 \times 10^{-8}$

$[H^{+}] = \frac{10^{-14}}{[OH^{-}]}$

= $\frac{10^{-14}}{0.0003}$

= $3.33 \times 10^{-11}$ M

Thus, we can conclude that the concentration of spectator ion is $3.33 \times 10^{-11}$ M.

5 0

3 years ago