Answer:
The genotypic frequency = 1:1
The phenotypic frequency = 1:1
Explanation:
Given that:
The allele → R = Red beetles
The allele → B = Blue beetles
Since the gene color shows a codominant allele
The Red Beetle = RR
The blue beetles will be = BB
The heterozygous beetle will be = RB
∴
The punnet square showing the crossing of RB × RR is:
R B
R RR RB
R RR RB
The result shows that we have two red beetles and two heterozygous beetles.
Hence;
The genotypic frequency = 1:1
The phenotypic frequency = 1:1
In sperm cells<span>, four haploid </span>gametes<span> are </span>produced<span>. In egg </span>cells<span>, </span>meiosis<span> results in a single haploid</span>gamete<span>, with the remainder of the genetic material lost in the formation of three nonviable polar bodies.</span>
I believe it’s an active dye?
It's empty or fairly large, making the sounds from your hands bounce of the walls and therefore having it echo
