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andrey2020 [161]
2 years ago
12

What is the LER for a rectangular wing with a span of 0.225m and a chord of 0.045m

Computers and Technology
1 answer:
ch4aika [34]2 years ago
4 0

Calculate LER for a rectangular wing with a span of 0.225m and a chord of 0.045m. The weight of the glider is 0.0500 Newtons. (Note: the wing span is the width of the wing and is measured from wing tip to wing tip, or perpendicular to the fuselage. The wing chord is the length of the wing measured parallel or along the length of the fuselage.)

Answer:

Area of rectangular wing = span × chord = 0.225×0.045= 0.010125m2

LER = Area/weight = 0.010125/0.0500 = 0.2025

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PLEASE HELP ME Jimmy and his friends are creating a rock band and have decided to turn his garage into a recording studio. He wa
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Answer:

D.  a studio monitor

Explanation:

A studio monitor is an electrical equipment that is used to enhance the quality of sound or music. It work like a speaker that can be used professionals to record audio songs, to make films and some other applications with good quality. It is usually used in studios where producer must ensures that the quality of music. As in music industry the quality of music depends on the quality of instrument used for the purpose of recording.

<em>This is the reason that, Jimmy and his friends should choose a Studio Monitor to achieve the most accurate sound quality.</em>

6 0
2 years ago
On a printed circuit board, electronic components will be mounted from the
Likurg_2 [28]
On a printed circuit board, electronic parts will be mounted from the substrate side of the board. The leads jab through the substrate and the copper sheeting that has been carved. The leads are then soldered to the copper.

I hope the answer will help you. 
3 0
2 years ago
Write a program that generates 1,000 random integers between 0 and 9 and displays the count for each number. (Hint: Use a list o
masya89 [10]

Answer:

import random

count0, count1, count2, count3,

count4, count5, count6, count7,

count8, count9, i = [0 for _ in range(11)]

while i < 1000:

   number = random.randint(0,9)

   if number == 0:

       count0 = count0 + 1

   if number == 1:

       count1 = count1 + 1

   if number == 2:

       count2 = count2 + 1

   if number == 3:

       count3 = count3 + 1

   if number == 4:

       count4 = count4 + 1

   if number == 0:

       count5 = count5 + 1

   if number == 6:

       count6 = count6 + 1

   if number == 7:

       count7 = count7 + 1

   if number == 0:

       count8 = count8 + 1

   if number == 9:

       count9 = count9 + 1

   

   i = i+1

print("0's: "+ str(count0) + "\n"+ "1's: "+ str(count1) + "\n"+

"2's: "+ str(count2) + "\n"+ "3's: "+ str(count3) + "\n"+

"4's: "+ str(count4) + "\n"+ "5's: "+ str(count5) + "\n"+

"6's: "+ str(count6) + "\n"+ "7's: "+ str(count7) + "\n"+

"8's: "+ str(count8) + "\n"+ "9's: "+ str(count9) + "\n")

Explanation:

- Initialize variables to hold the count for each number

- Initialize <em>i</em> to control the while loop

- Inside the while loop, check for the numbers and increment the count values when matched.

- Print the result

5 0
2 years ago
When light hits an opaque object it will be _______________.
nikklg [1K]
None of it passes through. Most of the light is either reflected by the object or absorbed and converted to heat. Materials such as wood, stone, and metals are opaque to visible light.

Good luck
7 0
1 year ago
Write a program that calculates and displays the number of minutes in a month. This program does not require any user input, and
dimulka [17.4K]

Answer:

Code to the answer is shown in the explanation section

Explanation:

import java.util.Scanner;

public class Question {

   public static void main(String args[]) {

     Scanner scan = new Scanner(System.in);

     System.out.println("Please enter the days of the month: ");

     int daysOfMonth = scan.nextInt();

     int minuteOfMonth = daysOfMonth * 60 * 24;

     System.out.println(minuteOfMonth);

   }

}

// 60 represents the number of minutes in one hour

// 24 represents the number of hours in a day

4 0
3 years ago
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