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3 years ago

What is the LER for a rectangular wing with a span of 0.225m and a chord of 0.045m

1 answer:

4 0

Calculate LER for a rectangular wing with a span of 0.225m and a chord of 0.045m. The weight of the glider is 0.0500 Newtons. (Note: the wing span is the width of the wing and is measured from wing tip to wing tip, or perpendicular to the fuselage. The wing chord is the length of the wing measured parallel or along the length of the fuselage.)

Answer:

Area of rectangular wing = span × chord = 0.225×0.045= 0.010125m2

LER = Area/weight = 0.010125/0.0500 = 0.2025

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nlexa [21]

Answer:

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3 years ago

How would I collect a number from the user to use for the radius of a circle?

exis [7]

Answer:

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3 years ago

The instant pivot button is displayed in the statistics and visualization tabs when a _______ search is run.

Arisa [49]

Answer:

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Explanation:

<h3>Transforming Search:</h3>

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Non-Transforming Search:

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4 years ago

The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices

erma4kov [3.2K]

Answer:

In Java:

import java.util.Scanner;

import java.util.Arrays;

public class Main {

public static void main(String args[]) {

Scanner input = new Scanner(System.in);

int row, col;

System.out.print("Rows: "); row = input.nextInt();

System.out.print("Cols: "); col = input.nextInt();

int[][] Array2D = new int[row][col];

System.out.print("Enter array elements: ");

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

int[] maxarray = findmax(Array2D,row,col);

System.out.println("Row: "+(maxarray[0]+1));

System.out.println("Column: "+(maxarray[1]+1));

}

public static int[] findmax(int[][] Array2D,int row, int col) {

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i;

maxitem[1] = j; } } }

return maxitem;

}

Explanation:

The next two lines import the scanner and array libraries

import java.util.Scanner;

import java.util.Arrays;

The class of the program

public class Main {

The main method begins here

public static void main(String args[]) {

The scanner function is called in the program

Scanner input = new Scanner(System.in);

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input

System.out.print("Rows: "); row = input.nextInt();

This next instructions prompt the user for columns and get the column input

System.out.print("Cols: "); col = input.nextInt();

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

This calls the findmax function. The returned array of the function is saved in maxarray

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col) {

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i; -- The row position is saved in index 0

maxitem[1] = j; -- The column position is saved in index 1} } }

This returns the 1 d array

return maxitem;

}

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3 years ago

There are two main types of hard drive available to a computer. State what they are and describe their use.

Gala2k [10]

Answer:

Hard disk drives (HDD), which use one or more rotating discs and rely on magnetic storage, and solid-state drives (SSD), which have no moving mechanical parts, but use flash memory like the kind found in USB flash drives.

Explanation:

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3 years ago