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jeka94
3 years ago
15

In order to avoid heavy traffic, Antonio can drive home after working less than 7 hours or after working more than 9 hours. How

can this be written as a single compound inequality?
7 h > 9
h 9
h > 7 or h < 9
Mathematics
1 answer:
NISA [10]3 years ago
4 0

Answer: h < 7 or h> 9

Step-by-step explanation:

just did the test

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3. What is the focus of the parabola?
Natalija [7]

(2, -1)

Just took the quiz.

4 0
3 years ago
Read 2 more answers
Plz, Help Me Quickly!!!
Lady bird [3.3K]

The equation of the horizontal ellipse is \frac{x^2}{144}+\frac{y^2}{100}=1

Ellipse is a plane curve surrounding two focal points, such that for all points on the curve, the sum of the two distances to the focal points is a constant.

The standard form of an ellipse with horizontal major axis is:

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

Where a > b

since a = 12, b = 10, hence:

\frac{x^2}{12^2}+\frac{y^2}{10^2}=1\\\\\frac{x^2}{144}+\frac{y^2}{100}=1

The equation of the horizontal ellipse is \frac{x^2}{144}+\frac{y^2}{100}=1

Find out more on ellipse at: brainly.com/question/19507943

7 0
3 years ago
What is the tens digit in the sum 7! + 8! + 9! + … + 2006!
Lena [83]

You can get the tens digit of any number <em>n</em> by computing the quotient

(<em>n</em> (mod 100)) / 10

and ignoring the remainder.

Taking the given sum (mod 100) gives

7! + 8! + … + 2006! ≡ 7! + 8! + 9! (mod 100)

since the last 1997 terms (i.e. 10! up to 2006!) in the sum are multiples of 100. That is,

• every term beyond 100! is obviously a multiple of 100

• every term beyond 25! contains a factor of both 4 and 25

• every term beyond 10! contains two factors each of both 2 and 5 (i.e. every factorial term contains 4, 5, and 10)

The remaining sum is easy to compute by hand:

7! + 8! + 9! = 7! (1 + 8 + 8 × 9) = 5040 × 81 = 408,240

so the tens digit is 4.

8 0
3 years ago
HELP!!!!!!ASAP!!!!!!​
Grace [21]

Answer:

Im only in middle school, sorry

Step-by-step explanation:

I have tips tho!

always write information down, only useful ones, and not like "jimmy love to play basketball" kin of stuff.

Think it through, dont just guess.

Hope this helps i guess,

-yuko

5 0
3 years ago
find the hypotenuse of each isosceles right triangle when the legs are of the given measure 6 square root of 2
tatiyna
A^2 + b^2 = c^2
(6√2)^2 + (6√2)^2 = c^2
(36)(2) + (36)(2) = c^2
72 + 72 = c^2
144 = c^2
√144=√(c^2)
c = 12
3 0
3 years ago
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