O raio é de 71,4 milímetros
142,8mm/2 = 71,4
The derivative of given function is H’(t) = 3 – 2/t3
A derivative is a two-party contract whose value/price is derived from an underlying asset. Futures, options, forwards, and swaps are the most prevalent types
Given that H(t)= t+ 1/t^2+2t+2
We must calculate the derivative
H(t)= t+ 1/t^2+2t+2
H(t) = 3t + 1/t^2 + 2
H’(t) = d/dt(3t + 1/t^2 + 2)
H’(t) = d/dt(3t) + d/dt (1/t^2) + d/dt ( 2)
H’(t) = 3xd/dt(t) + d/dt (1/t^2) + d/dt ( 2)
H’(t) = 3xd/dt(t) + d/dt (t-2) + d/dt ( 2)
H’(t) = 3 – 2t-3
H’(t) = 3 – 2/t3
Therefore the derivative of the given function is H’(t) = 3 – 2/t3
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The average rate of change from an interval from
to
is the change in the value of the function divided by the change in x.
Let's find the values of
and
Average rate of change
Your answer is 7. I hope this helps! :)
Answer:
find the area if the sector,then the area of the triangle.After that, Subtract the area of the triangle from the area of the sector
Answer: -2
Step-by-step explanation:
divide 8 by 4 like regular and add the negitive
