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goldfiish [28.3K]
2 years ago
8

He wants to earn 481$ By mowing lawns and he charge $22 for each long what is the maximum number of lungs that he needs to mow t

o reach his goal of $481
Mathematics
1 answer:
Reika [66]2 years ago
6 0

\stackrel{\stackrel{total~amount}{goal}}{481}~~ = ~~22(lawn)\implies \cfrac{481}{22}=lawn\implies \stackrel{rounded}{22}\approx lawn

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Stefanie bought a package of pencils for $1.75 and some erasers that cost $0.25 each. She paid a total of $4.25 for these items,
melamori03 [73]

Answer:

Stefanie bought 10 erasers

Step-by-step explanation:

We can establish the following equation:

TP = NP*PP + NE*EP

Where:

TP = Total price; (4.25)

NP = Number of pencil packages; (1)

PP = Pencil Package's Price; (1.75)

NE = Number of erasers; (What we are looking for)

EP = Erasers Price; (0.25);

Then:

4.25 = 1*1.75 + NE*0.25;

4.25 - 1.75 = NE*0.25;

2.5/0.25 = NE;

10 = NE.

5 0
4 years ago
Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact
scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}

    =\frac{(55-1)\times 94.7}{75}\\\\=68.184

The test statistic value is, 68.184.

Decision:

cal.\chi^{2}=68.184

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0
3 years ago
You worked 5.5 hrs on Sunday +12 hrs on monday + 9.5 hrs on Tuesday + 11 hrs on Wednesday + 7 hrs on Thursday + 10 hrs on Friday
Alik [6]

Worked an average of 9 hours per day

3 0
3 years ago
Solve -3x + 12 = x – 4<br><br> Show your work
jeka94

Answer:

Step-by-step explanation:

-3x +12 =x-4

+3x

12 = 4x -4

+4

16 = 4x

Divide by 4

4 = x

3 0
4 years ago
Read 2 more answers
What is the solution of -3 = x +5
drek231 [11]
X=-8

A negative plus a positive, if ghe negative is bigger it stays negative. -8 is bigger than 5 and 8 - 5 is 3 add the negative and you get -3
4 0
3 years ago
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