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kifflom [539]
2 years ago
15

Draw the projection when point X is 20 mm above HP and 30 in front of the VP. The line XY is 75 mm long and its Elevation length

measures 60 mm. Find the inclination with VP only.
Mathematics
1 answer:
creativ13 [48]2 years ago
8 0
Seval ozhabes Seval your your dad is ygoing urueiei ieieuieieieieieueue basorospu
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What is the exact volume of the figure?
uranmaximum [27]

Answer: 890.12 cm^3

Step-by-step explanation:

The formula for the volume of a cylinder is

V=\pi *r^2*h

V=628.3185307 cm^3

or simply

V=628.32 cm^3

Since, you know the radius of the hemisphere on top, you also know the radius since the height of the hemisphere is the same as it is wide.

Next, the formula for the volume of a sphere is

V=\frac{4}{3} \pi *r^3

so the volume of a hemisphere is half of that or:

V=\frac{2}{3} *\pi *r^3

V= 261.7993878 cm^3

or simply

V=261.80 cm^3

Finally, you add both of the volumes together to get

V= 890.1179185 cm^3

or simply

V=890.12 cm^3

7 0
3 years ago
Write 9x² - 36x = 4y² + 24y + 36 in standard form
Kisachek [45]

Answer:

9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;

(x - 2)²/2² - (y + 3)²/3² = 1

Step-by-step explanation:

The standard form of a hyperbola is given as follows;

(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1

The given equation is presented as follows;

9·x² - 36·x = 4·y² + 24·y + 36

By completing the square, we get;

(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)

(3·x - 6)² - 36 = (2·y + 6)²

(3·x - 6)² - (2·y + 6)² = 36

(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1

(3·x - 6)²/6² - (2·y + 6)²/6² = 1

3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1

(x - 2)²/2² - (y + 3)²/3² = 1

The equation of the hyperbola  is (x - 2)²/2² - (y + 3)²/3² = 1.

5 0
3 years ago
Please i need help ASAP<br><br>What is the range? ​
Lena [83]

Answer:

your range is -9 to positive 5

Step-by-step explanation:

range is how many numbers are in a squence for example i have 1 2 3 so my range is 1-3

8 0
3 years ago
Sum of two numbers is -17. Their difference is 41. Find the numbers
wel

Answer:

Suppose~the~two~numbers~are~x~and~y.\\From~the~first~condition,\\x+y=-17...........(1)\\From~the~second~condition,\\x-y=41.............(2)\\Adding~eq^n(1)~and~eq^n(2),~we~get,\\x+y+x-y=-17+41\\or, 2x = 24\\or, x=12\\Substituting~x=12~in~eq^n(2),\\y = -17-x = -17-12 = -29

So,~the~two~numbers~are~12~and~-29.

3 0
3 years ago
Let AB 0, n(A) = 3 and n(B) = 5<br> be given. Find max value of n(AUB).
yuradex [85]

Answer:

(3,5)

Step-by-step explanation:

n(AUB)=(3)U(5)

=(3,5)

8 0
3 years ago
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