Answer:

Step-by-step explanation:
Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:
First airplane

Where t is the time measured in hours.
Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

Rate of change of such distance can be found by the deriving the expression in terms of time:

Where
and
, respectively. Distances of each airliner at 2:30 PM are:


The rate of change is:


Happy birthday, and the answer would be 3m(squared). The formula is LxH/2.
Answer:
x + 3y + 9 = 0
Step-by-step explanation:
y=3x + 2
Coefficient of x = 3
Gradient (m) of line y= 3x + 2 is 3
Since the line passing through point
(3,-4) is perpendicular to line y=3x + 2
hence gradient (m) of the line is -1/3;
And hence it equation is given as;
y - y1 = m(x - x1)
y - (-4) = -1/3(x - 3)
multiplying through by 3;
3 × y + 3 × 4 = 3 × -1/3(x - 3)
3y + 12 = -1(x - 3)
3y + 12 = -x + 3
x + 3y + 12 - 3 = 0
x + 3y + 9 = 0
Answer:
<h2>D) - 9/7</h2>
Hope this will help you lot.
So 6+3 is 9 right? So let's just say it's 9:37 with a 45 min ride. 60 minutes are in a hour. 60 - 37 = 23. We have 23 minutes left until 10:00. 45- 23 = 22. Therefore it'd be 10:22 p.m.