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3 years ago

CAN ANYONE HELP ME WITH REALTIONSHIPS WITHIN TRIANGLES?

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

4 0

M<YZW=90 degrees
m<V=40
180-(90+40)
180-130 = 50
the measure of VWZ is 50 degrees

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When identifying properties of n - sided polygons where 3 _< n <_ 10. What does 3 <_ n <_ 10 means ?

Lunna [17]

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Answer:

3 ≤ n ≤ 10 means "three is less than or equal to n, which is less than or equal to 10"

you're concerned with polygons having 3 to 10 sides, inclusive.

Step-by-step explanation:

The symbol ≤ means "less than or equal to." The compound inequality ...

3 ≤ n ≤ 10

means the value of n may range from 3 to 10, inclusive.

In the present context, where n is a number of sides, it means you're concerned with polygons that are any of ...

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3 years ago

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yulyashka [42]

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3 years ago

What is the value of x? A. 3cm B. 4cm C. 5cm D. 4.5cm

Alexxx [7]

Answer:

5 cm

Step-by-step explanation:

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2 years ago

Find the following:

Butoxors [25]

Answer:

Step-by-step explanation:

Limit refers to the value that the function approaches as the input approaches some value.

We say $\displaystyle \lim_{x\rightarrow a}f(x)=L$ , if f(x) approaches L as x approaches 'a'.

(a)

$\displaystyle \lim_{x\rightarrow 5}\left ( \frac{f(x)-8}{x-5} \right )=4\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-\displaystyle \lim_{x\rightarrow 5}8}{\displaystyle \lim_{x\rightarrow 5}x-\displaystyle \lim_{x\rightarrow 5}5}=4\\$

$\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-8}{\displaystyle \lim_{x\rightarrow 5}x-5}=4\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=4\left ( \displaystyle \lim_{x\rightarrow 5}x-5 \right )\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=4\displaystyle \lim_{x\rightarrow 5}x-4(5)\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=4(5)-4(5)\\$

$\displaystyle \lim_{x\rightarrow 5}f(x)-8=20-20=0\\\displaystyle \lim_{x\rightarrow 5}f(x)=8$

(b)

$\displaystyle \lim_{x\rightarrow 5}\left ( \frac{f(x)-8}{x-5} \right )=7\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-\displaystyle \lim_{x\rightarrow 5}8}{\displaystyle \lim_{x\rightarrow 5}x-\displaystyle \lim_{x\rightarrow 5}5}=7\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-8}{\displaystyle \lim_{x\rightarrow 5}x-5}=7\\$

$\displaystyle \lim_{x\rightarrow 5}f(x)-8=7\left ( \displaystyle \lim_{x\rightarrow 5}x-5 \right )\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=7\displaystyle \lim_{x\rightarrow 5}x-7(5)\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=7(5)-7(5)\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=35-35=0\\\displaystyle \lim_{x\rightarrow 5}f(x)=8$

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3 years ago