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Alekssandra [29.7K]
2 years ago
9

2x+9>17 or 5x+10<10 compound inequalities

Mathematics
2 answers:
irina1246 [14]2 years ago
4 0

0<x>4

the value of x lies between 0 and 4.

A compound inequality is an inequality that combines two simple inequalities. A compound inequality is made up of two inequalities connected by the word “and” or the word “or.” To solve a compound inequality means to find all values of the variable that make the compound inequality a true statement.

lets take 2x+9>17

now lets subtract 9 from both sides.

2x + 9 > 17

     - 9 > -9

2x > 8

now divide both sides by 2

2x ÷ 2 > 8 ÷ 2

x > 4

lets take the second part i.e 5x +10 <10

substract 10 from both sides

5x + 10 < 10

     - 10 < -10

5x < 0

now divide both sides by 5

5x ÷ 5< 0 ÷ 5

x < 0

0<x>4

the value of x lies between 0 and 4.

To learn more about compound inequalities visit,  brainly.com/question/28578031

#SPJ9

Natali [406]2 years ago
3 0

Answer: 2x+9>17 or  5x+10<10 compound inequalities is x<0

Step-by-step explanation:

What is Meant by Compound Inequality?

In Mathematics, a compound inequality is a sentence which has two statements connected using the word “and” or by the word “or”. If the statements are connected using the word “and”, then both the statements of the compound sentence are true at the same time. If the statements are connected using “or”, then the compound sentence is true if at least one statement is true.

2x+9>17 or  5x+10<10

Let take 2x+9>17

Subtract -9 on both sides

2x+9-9>17-9

2x+0>8

2x>8

Now we need to divide by 2 both sides

2x÷2>8÷2

x>4

Now we solve 5x+10<10

we need to subtract -10 on both side

5x+10-10<10-10

5x+0<0

5x<0

Now we need to divide  5 on both sides

5x÷5<0÷5

x<0

Learn more about area here https://brainly.in/question/19328677

#SPJ9

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The length of a rectangle is
melomori [17]

Answer:

L= 11 m and W = 2 m

Step-by-step explanation:

Let's convert the sentences into mathematical expressions, for which we need to assign letters to the unknowns: length and width of a rectangle.

Let's identify the rectangle's length with the letter "L', and its width with the letter "W".

Then we can write:

"The length of a rectangle is  3  meters more than  4  times the width."

as: L = 4 * W + 3

The second sentence says:

"The area (of the rectangle) is 22 square meters", so to write this in mathematical terms we need to recall the formula for the area of a rectangle:

Area = Length * Width   (the product of the rectangle's length times its width)

Therefore the second sentence can be converted into the following equation:

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Now we can use the first mathematical expression we constructed in the second formula so we can reduce the number of unknowns  from two (L and W) to only one (W) and solve for it in the equation.

We replace "L" with 4 * W + 3 (from our first expression) in the area formula:

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x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

For our unknown W (instead of "x") and our parameters:

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the quadratic formula would be:

W=\frac{-3+/- \sqrt{3^2-4(4)(-22)} }{2(4)}=\frac{-3+/- \sqrt{9+352} }{8}= \frac{-3+/- \sqrt{361} }{8}=\frac{-3+/-19 }{8}This gives as two possible solutions (one using the plus and the other using the minus):

W=\frac{-3-19}{8} =\frac{-22}{8}=-\frac{11}{4} \\W=\frac{-3+19}{8} =\frac{16}{8}=2 \\

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Now we use the first expression we found for "L" to find its value:

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Step-by-step explanation:

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