Answer:

<h3><u>For the 1st part</u></h3>




<h3><u>For the 2nd part</u></h3>
<u />



Answer:
0
Step-by-step explanation:
4-6 is -2 and |3-5| is -2 but the |-2| makes it 2 so -2+2=0 so 0/3=0
Solution:
we are given that
A six sided number cube has faces with the numbers 1 through 6 marked on them.
we have been asked to find the probability that a number less than 2 will occur on one toss of the number cube.
Since a number less than 2 is only one and that is "1" and total number of possible outcome is 6.
and as we know that probability is given using the formula

Substitute the values we get

Hence the required probability is 1/6.