The result of rolling a number cube 7 times is a 7-digit number composed of digits 1,2,3,4,5 and 6 so that digits can repeat. The total number of possibilities is 6^7.
The number of possibilities where 4 appears exactly two times is 5^5*(7!-6!/2).
5^5 is the number of 5-digits numbers composed of digits 1,2,3,5 and 6 so that digits can repeat.
7! is the number of permutations of digits 1,2,3,4,4,5 and 6.
6! is the number of permutations of digits 1,2,3,{4,4},5 and 6.
We don't want to subtract all numbers where digits 4 appear side by side. That's why we must divide 6! by 2.
Finally, the probability is P=5^5(7!-6!/2)/7^7
If you mean the m^3=105, then m^6 will be
![( \sqrt[3]{105}) ^6](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B3%5D%7B105%7D%29%20%5E6)
which is 105^2 which is
11025
Answer:
C
Step-by-step explanation:
There is a common ratio between consecutive terms
r = 24 ÷ 16 = 36 ÷ 24 = 54 ÷ 36 = 1.5 = 
This indicates the sequence is geometric with nth term ( explicit formula )
f(n) = a₁
where a₁ is the first term and r the common ratio
Here a₁ = 16 and r = , then
f(n) = 16 
→ C
Answer:
B. x =1 , y = -5
Step-by-step explanation:
So, what we can do is to simply plug in all of the equations and see which one fits. Equation: x - y = 6
A. x =1 , y = -6
1 -(-6) = 6
1 + 6 = 7
A would be incorrect.
B. x = 1, y = -5
1 - (-5) = 6
1 + 5 = 6
Therefore, B would be correct.
This is a diffficult question was there a chart
