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Yakvenalex [24]
4 years ago
13

Solve for x type your answer as x = (#) ASAP

Mathematics
2 answers:
uysha [10]4 years ago
8 0

Answer: 1=4

2=18

3=7

4=5

two step:

1=6

2=4

3=4

Step-by-step explanation: they might be wrong so pls check so u don’t get them wrong

Nataliya [291]4 years ago
3 0

Answer:

One step Equations:

1. x=4

2. x=18

3. x=3

4. ×=50

Two Step Equations:

1. x= 7

2. x= -4

3. x= 24

Variations on Both Sides:

(I'm not sure if these are right but the answers above are for sure correct)

1. x= 4.5

2. x= -2

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What is the solution of the equation? 3(y-5)+2=5​
Marizza181 [45]

Answer:

Y=- 6

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3y-15+2=5

add

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add pos 13 to the neg 13 to

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divide -3 to pos 3 and 18 to cancel it out

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3 years ago
 can you help me solve the equation: 5m+3=18
shtirl [24]
5m+3=18\ \ \ \ \ |subtract\ 3\ from\ both\ sides\\\\5m=15\ \ \ \ \ \ \ |divide\ both\ sides\ by\ 5\\\\\boxed{m=3}
5 0
4 years ago
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The sick days of employees every two years in a company are normally distributed with a population standard deviation of 7 days
Alecsey [184]

Answer:

The 95% confidence interval for the population mean is between 17.93 days and 24.07 days.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{7}{\sqrt{20}} = 3.07

The lower end of the interval is the sample mean subtracted by M. So it is 21 - 3.07 = 17.93 days

The upper end of the interval is the sample mean added to M. So it is 21 + 3.07 = 24.07 days

The 95% confidence interval for the population mean is between 17.93 days and 24.07 days.

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4 years ago
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Step-by-step explanation:

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How many times does 3 go into 32
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Step-by-step explanation:

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4 years ago
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