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Molodets [167]
2 years ago
12

Find the longest wavelengths of light that can cleave the bonds in elemental nitrogen, oxygen, and fluorine.

Chemistry
1 answer:
Angelina_Jolie [31]2 years ago
6 0

Longest wavelengths of light that can cleave the bonds in elemental nitrogen ,oxygen, fluorine is 1.27 x 10⁻⁷ m ,2.40 x 10⁻⁷ m,7.52 x 10⁻⁷ m

How do you calculate wavelength?

  • Longest wavelengths of light that can cleave the bonds in elemental nitrogen

         wavelength = NA x h C / bond energy

                             = 6.022 x 10²³ x 6.626 x 10⁻³⁴ x 3 x 10⁸ / (945 x 10³)

                             = 1.27 x 10⁻⁷ m

  • Longest wavelengths of light that can cleave the bonds in elemental Oxygen

         wavelength = NA x h C / bond energy

                             = 6.022 x 10²³ x 6.626 x 10⁻³⁴ x 3 x 10⁸ / (498 x 10³)

                             = 2.40 x 10⁻⁷ m

  • Longest wavelengths of light that can cleave the bonds in elemental Fluorine

        wavelength = NA x h C / bond energy

                           = 6.022 x 10²³ x 6.626 x 10⁻³⁴ x 3 x 10⁸ / (159 x 10³)

                           = 7.52 x 10⁻⁷ m

Where ,

NA is Avogadro's number

h is Planck's constant

C is speed of light.

So, the longest wavelengths of light that can cleave the bonds in elemental nitrogen ,oxygen, fluorine is 1.27 x 10⁻⁷ m ,2.40 x 10⁻⁷ m,7.52 x 10⁻⁷ m.

learn more about wavelength here:

brainly.com/question/6297363

#SPJ4

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Complete question:

The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.44×10⁻⁴ s⁻¹ at a certain temperature.

If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?

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After 210 s the concentration of SO2Cl2  will be 0.121 M

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