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2 years ago

The population that experienced the highest radioactivity from chernobyl in norway were:______

1 answer:

5 0

The population that experienced the highest radioactivity from chernobyl in norway were "a small community of reindeer herders called the Saami".

Typically, the term "population" denotes the total quantity of people living in a particular area, be it a city or town, region, country, continent, or even the entire world.

The native reindeer herders of Scandinavia could be known as the Sámi. These breathtaking images capture a herd during its yearly journey through summer pastures as well as wintering areas.

Therefore, the population that experienced the highest radioactivity from chernobyl in norway were "a small community of reindeer herders called the Saami".

To know more about population

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3 years ago

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3 years ago

What is the density of motor oil in g/mL if 1.25 quart (qt) weighs 2.25 pounds (lb)?

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Answer:

0.86 g/mL

Explanation:

In order to solve the problem, you have to know the formula for "Density." Density refers to "mass per unit volume." It's formula is:

Density (ρ) = $\frac{mass}{Volume}$

Next, we have to convert the units of measurement in accordance to what is being asked in the problem. It is asking for "g/mL," which means we have to convert 1.25 quarts (qt.) to mL and 2.25 pounds (lbs.) to grams.

Let's solve.

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2.25 pounds x $\frac{453.592 grams}{1 pound}$ = 1,020.58 grams

Now that we converted them to their appropriate units of measurement, we can now solve for density.

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ρ = $\frac{1,020.58 grams}{1,182.94 mL}$

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The density of the motor oil is 0.86 g/mL

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3 years ago

ASAP MULTIPLE CHOICE WILL MARK BRAINLIEST

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Explanation:

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4 years ago

(1) ClO-(aq) + H2O(l) HClO(aq) + OH -(aq) [fast] (2) I -(aq) + HClO(aq) HIO(aq) + Cl -(aq) [slow] (3) OH -(aq) + HIO(aq) H2O(l)

Sergeeva-Olga [200]

Answer:

ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq)

Explanation:

The reactions are:

(1) ClO⁻(aq) + H₂O(l) → HClO(aq) + OH⁻(aq) [fast]

(2) I⁻(aq) + HClO(aq) → HIO(aq) + Cl⁻(aq) [slow]

(3) OH⁻(aq) + HIO(aq) → H₂O(l) + IO⁻(aq) [fast]

By adding up the 3 equations we get:

ClO⁻(aq) + H₂O(l) + I⁻(aq) + HClO(aq) + OH⁻(aq) + HIO(aq) → HClO(aq) + OH⁻(aq) + HIO(aq) + Cl⁻(aq) + H₂O(l) + IO⁻(aq)

And by canceling common terms on both sides, we can get the overall equation:

ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq)

Therefore, the overall equation is ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq).

I hope it helps you!

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3 years ago