Question

Calculate the mass defect and the nuclear binding energy of nitrogen-14. The mass of a proton is 1.00728 amu, and the mass of a neutron is 1.00866 amu. The mass of a nitrogen-14 atom is 14.00307 amu.

Answer 1

Answer:The binding energy of the nitrogen nucleus is $6.26\times 10^{28} MeV$.

Explanation:

Atomic mass of the nitrogen,$M_A$ =14.00307 amu

Number of protons, Z = 7

Number of neutrons,N = Atomic mass - number of protons

=14.0037 - 7 =7.00307

Mass of proton ,$m_p=1.00728 amu$

Mass of neutron,$m_n=1.00866 amu$

$\Delta m=(Zm_p+Nm_n)-M_A=(7\times 1.00728 amu+7.00307\times 1.00866 amu)-14.00307 amu$

$\Delta m=0.11160 amu$

Binding energy =$\Delta m\times c^2=0.11160 amu\times (3\times 10^8 m/s)^2=1.0044\times 10^{16} Joules$

$1.0044\times 10^{16} Joules=6.26\times 10^{28} MeV,(1J=6.24\times 10^{12} MeV)$

The binding energy of the nitrogen nucleus is $6.26\times 10^{28} MeV$.

Answer 2

The mass defect of Nitrogen-14 is 0.10851

The nuclear binding energy of one Nitrogen-14 atom is 1.62

A: -11